I have a question about this fraction question

Mathematics

1 answer:

Misha Larkins [42]2 years ago

8 0

Answer:

where's the question I'm confused

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A ball thrown in the air vertically from ground level with initial velocity 37 m/s has height h(t) = 37t − 4.9t2 m at time t (in

Nesterboy [21]

Answer:

46.57

Step-by-step explanation:

Given that:

h(t) = 37t - 4.9t²

When the ball reaches the ground, then the height is zero;

So, we equate h(t) to zero and solve for t

37t - 4.9t² = 0

t = 0, 7.55

Let the Initial time be a = t = 0

The time the ball reaches the ground be b = 7.55

So, the average height can now be calculated as:

Average height = $\frac{1}{b-a}\int\limits^b_a {h(t)} \, dt$

= $\frac{1}{7.55-0}\int\limits^{7.55}_0 (37t-4.9^2) dt$

= $\frac{1}{7.55-0}\ (\frac{37(7.55)^2}{2} - \frac {4.9(7.55)^3}{3})$

= $\frac{1}{7.55-0}\ (351.6104208)$

= 46.57091665

≅ 46.57 to (2 decimal places)

6 0

3 years ago

suppose that you are headed toward a plateau 80 meters high. if the angle of elevation to the top of the plateau is 35 degree, h

slega [8]

We are 114.28 m from the base of the plateau .

<u>Step-by-step explanation:</u>

Here we have , suppose that you are headed toward a plateau 80 meters high. if the angle of elevation to the top of the plateau is 35 degree, WE need to find that how far are you from the base of the plateau . If we see in question , it's clearly a question from application of trigonometry :

We have ,

$Perpendicular = 80 m$