Question

Find the sum for: (3x^2+4x−1)+(−2x^2−3x+2)=

Answer 1

Answer:

x^2+x+1

Step-by-step explanation:

(3x^2+4x−1)+(−2x^2−3x+2)

Combine like terms

3x^2-2x^2+4x-3x-1+2

x^2+x+1