Find the sum for: (3x^2+4x−1)+(−2x^2−3x+2)=
1 answer:
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Answer:
(x + 2)(x - 5)
Step-by-step explanation:
Here are the steps:
Going to put your function in slope-intercept form for the sake of easier input into Desmos.
y - 2 = - (x + 5)
y - 2 = - x - 5
y = - x - 5 + 2
y = - x - 3
y - 2 = - (x + 5)
y - 2 = - x - 5
y = - x - 5 + 2
y = - x - 3