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3 years ago

The area of a circular swimming pool is approximately 18m What is the radius

Mathematics

2 answers:

Ulleksa [173]3 years ago

8 0

Answer:

Hiiiiiiii ! :) so here's a step by step explanation okay, starting with the first step below. Hope it helps you ! :) :)

Step-by-step explanation:

Begin with the volume of water:

V = πr²×h = π×(9m)²×2.5m = 636.17m³

Weight of water = 636.17×10³kg

G force on water = 9.8m/s²×636.17×10³kg = 6,234.49kN

Water's center of gravity is 2.75m below edge of pool.

(2.5m/2 = 1.25m, 4m - 1.25m = 2.75m)

Work = force × distance = 6,234.49kN × 2.75m = 17,144.85

Hope i helped. <3

olga nikolaevna [1]3 years ago

7 0

Answer:

r≈2.39

Step-by-step explanation:

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Perfect square between 1 and 9

Rasek [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

Hi, may someone help me with this question? Thank you!:) “If f(x) = x^2 + 7, find f(x+2)”

finlep [7]

Answer:

=x^2 +4x+11

Step-by-step explanation:

f(x) = x^2 + 7,

Replace x with x+2

f(x+2) = (x+2)^2 + 7

= (x+2)(x+2) +7

FOIL

= x^2 +2x+2x+4 +7

Combine like terms

=x^2 +4x+11

5 0

3 years ago

Read 2 more answers

A car traveling at 88 km an hour over takes a bus traveling at 64 km an hour if the bus has a 1.5 hour Headstart how far from th

PIT_PIT [208]

Answer: 352 miles

Step-by-step explanation:

At the point where the car overtook the bus, the car and the bus would have travelled the same distance.

Let x represent the distance covered by bus and the car before the car overtook the bus.

Let t represent the time taken by the bus to travel x miles.

The bus was traveling at 64 km an hour.

Distance = speed × time

Distance travelled by the bus in t hours would be

x = 64 × t = 64t

if the bus has a 1.5 hour Headstart, it means that the car started moving 1.5 hours after the bus has moved.

Therefore, time spent by the car would be t - 15 hours.

The car traveling at 88 km an hour

Distance covered by the car in t - 1.5 hours would be

x = 88(t - 1.5) = 88t - 132

Since the distance covered is equal, then

88t - 132 = 64t

88t - 64t = 132

24t = 132

t = 132/24

t = 5.5 hours

Therefore, the distance from the starting point when the car overtook the bus would be

x = 64 × 5.5 = 352 miles

3 0

3 years ago

QUESTION in the diagram below the following are rectangles. ACEG ;BCDJ ; JDEF and HJFG is a square AB =AH = x ;BC=5 ; HG=3 Area

White raven [17]

The area of the rectangle ACEG is the amount of space on it, and the area of square HJFG is 9 square units

<h3>How to determine the area of the figures?</h3>

The area of a rectangle is:

Area = Length * Width

The area of a square is:

Area = Length * Length

From the question, the given parameters are:

AB =AH = x ;

BC=5;

HG=3

This means that the area of square HJFG is:

Area = HG * HG

Area = 3 * 3

Area = 9

Note that the other areas cannot be calculated because the question is incomplete

Read more about areas at:

brainly.com/question/17335144

#SPJ1

7 0

2 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

The area of a circular swimming pool is approximately 18m What is the radius​

The area of a circular swimming pool is approximately 18m What is the radius