Answer:
I can help you, just tell me what it is.
Step-by-step explanation:
Step 1: Tell me the problem
Step 2: Wait for a response.
Answer:
Length = 49.5 unit and width = 49.5 unit
Step-by-step explanation:
Given as , Perimeter of rectangle = 198 unit
so ,as Perimeter of rectangle = 2× ( Length + width)
Or, 198 = 2 × (Length + width)
Or,
= length + width
So, length + width = 99 unit
Now to make area maximum
Length × width = maximum
Or, (99 - width ) × width = maximum
99 Width - width² = maximum Let width = W
Now differentiate both side with respect to W
D(99W - W²)
= 0 as, constant diff is 0
So, 99 - 2w = 0
Or, w = 
Or, w = 49.5 unit and L = 99- 4905 = 49.5 unit Answer
The answer to your question is 2/7 is 1/2 of 1 3/4.
Answer:
50 ft²
Step-by-step explanation:
If W is the width and L is the length, then:
L = W + 5
2L + 2W = 30
Solve the system of equations with substitution or elimination. Using substitution:
2(W + 5) + 2W = 30
2W + 10 + 2W = 30
4W = 20
W = 5
L = 10
The area of the rectangle is:
A = LW
A = 50 ft²
Answer:
402.12
Step-by-step explanation:
V=πr2h= π·42·8≈402.12386