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kow [346]
3 years ago
10

Find the value of tan F rounded to the nearest hundredth , if necessary

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0

Using it's formula, it is found that the tangent of F is given by:

  • \tan{F} = \frac{6\sqrt{85}}{85}

<h3>How to find the tangent of an angle?</h3>
  • In a right triangle, the tangent of an angle is given by the length of the opposite leg divided by the length of the adjacent leg.

Researching the problem in the internet, it is found that for the <em>right triangle</em> in this problem:

  • The length of the opposite leg to angle F is of 6.
  • The length of the adjacent leg to angle F is of x.
  • The length of the hypotenuse is of 11.

Applying the Pythagorean Theorem, we have that:

6^2 + x^2 = 11^2

36 + x^2 = 121

x^2 = 85

x = \sqrt{85}

Considering that the tangent is the length of the opposite leg divided by the length of the adjacent leg, we have that:

\tan{F} = \frac{6}{\sqrt{85}} \times \frac{\sqrt{85}}{\sqrt{85}} = \frac{6\sqrt{85}}{85}

To learn more about tangent, you can take a look at brainly.com/question/24680641

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I’m pretty sure it’s d because 2 is how much the cells have multiplied by hour say you started with 3 and it been three hours you would have 24 cells because it double the amount every time 3*2=6*2=12*2=24
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What is the slope-intercept form of the function described by this table?
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Nothing will "break" this function as it is a cubed root. Thus the output (range) could be anything
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A triangle has vertices at (-1,5), (4,2), and (0,0). What is the perimeter of the triangle
yan [13]

The perimeter of the triangle is 15.4 units.

<u>Step-by-step explanation:</u>

The triangle has vertices at (-1,5), (4,2), and (0,0).

To find the perimeter of the triangle, you need to find the distance of the three points which is the length of the three sides of the triangle.

Let us consider the points as A (-1,5) and B (4,2) and C (0,0).

<u>The distance formula is given by :</u>

⇒ \sqrt{(x2-x1)^{2}+(y2-y1)^{2}  }

<u>Distance of AB :</u>

A (-1,5) ⇒ (x1,y1)

B (4,2) ⇒ (x2,y2)

⇒ \sqrt{(4+1)^{2}+(2-5)^{2}  }

⇒ \sqrt{5^{2}+-3^{2}  }

⇒ \sqrt{25+9}

⇒ \sqrt{34}

⇒ 5.8

∴ The length of the side AB of the triangle is 5.8 units.

<u>Distance of BC :</u>

B (4,2) ⇒ (x1,y1)

C (0,0) ⇒ (x2,y2)

⇒ \sqrt{(0-4)^{2}+(0-2)^{2}  }

⇒ \sqrt{16+4  }

⇒ \sqrt{20}

⇒ 4.5

∴ The length of the side BC of the triangle is 4.5 units.

<u>Distance of CA :</u>

C (0,0) ⇒ (x1,y1)

A (-1,5) ⇒ (x2,y2)

⇒ \sqrt{(-1-0)^{2}+(5-0)^{2}  }

⇒ \sqrt{1+25}

⇒ \sqrt{26}

⇒ 5.1

∴ The length of the side CA of the triangle is 5.1 units.

Now, the perimeter of the triangle is given by :

Perimeter = Sum of the lengths of all three sides of the triangle.

⇒ 5.8 + 4.5 + 5.1

⇒ 15.4 units.

∴ The perimeter of the triangle is 15.4 units.

4 0
3 years ago
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