Answer:
Step-by-step explanation:
![7- \sqrt[3]{2-x} =12](https://tex.z-dn.net/?f=7-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D12)
we have to just keep in mind to do the same operation to both sides of the equal sign
; subtract 7 from both sides
; multiply both sides by -1
; raise both sides to the power 3
2-x = (-5)³
2-x = -125 ; subtract 2 from both sides
-x = -125-2
-x =-127; multiply both sides by -1
x= 127
There are 10 marbles total.
Since there's only one red, the chance of getting a red marble is
Answer:
original width= 9.6 feet
original length = 38.4 feet
Step-by-step explanation:
Hi, to answer this question we have to apply the formula
P =2w +2 L
Where:
P=perimeter
W= width
L = length
Since the field is 4 times as long as it is wide
L= 4W
So, if the length is decreased by 10 feet and the width is increased by 2 feet, the perimeter will be 80 feet.
Mathematically speaking
80= 2 (W+2) + 2(L-10)
Simplifying:
80 = 2w+4 +2L-20
Replacing the value of L by 4W
80 = 2W +4 +2(4W)-20
Solving for W:
80=2W +4 +8W-20
80-4+20= 2W+8W
96= 10W
96/10 =W
W= 9.6 feet
Replacing the value of W in the Length equation:
L =4W
L = 4 (9.6)
L = 38.4 feet
Answer:
7, -1
Step-by-step explanation:
x^2 - 6x + 7 = 0
(x - 7)(x + 1) = 0
==> x = 7, x = -1
Answer:
0.60
Step-by-step explanation:
In the category of pets
22 students had a cat = P(C)
17 students had a dog = P(D)
9 students had both a dog and a cat = P(C and D)
The formula to find the Probability of two events =
P(C or D) = P(C) + P(D) - P(C and D)
P(cat or dog) = P(cat) + P( dog) - P(cat and dog)
P(cat or dog) = 22/50 + 17/50 - 9/50
P(cat or dog) = 0.44 + 0.34 - 0.18
P(cat or dog) = 0.60
The probability the student will have a dog or a cat is 0.60