Answer:
false
Explanation:
parasynthesis is used to change the order of priority.
Answer:
Bell
Explanation:
In the given case the product that has the highest Dec. Cust. Survey score will be treated as most competitive at the end of last year. Based on the information provided in the "Top Products in Thrift Segment" table, we can conclude that Bell has highest score for Dec. Cust. Survey score which stands at 31.
Please see attachment for the product list we referenced to as non was given.
To delete only the selected contents of the table, but not the table itself, you need to click on this cell in the table.
Answer:
F(a,b,c,d)=b'c' + a'cd' + ab'd'.
Explanation:
The image of the corresponding k-map is attached to this answer please refer it.By the sop given in the question the k-map is formed.There are 3 groups formed 1 group of four 1's and 2 groups of 2 1's.Hence there are three sop and the sop is reduced from the previous SOP.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
