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8090 [49]
2 years ago
5

The three altitudes of a triangle intersect at the:

Mathematics
1 answer:
Oxana [17]2 years ago
7 0
<h3>Answer: orthocenter</h3>

Explanation:

An altitude of a triangle extends from one vertex to the opposite side, where this altitude is perpendicular to the opposite side. The term "altitude" is often interchanged with "height". Think of a tall mountain that has a lot of altitude, so it's got a lot of height.

Any triangle has 3 different altitudes (one per corner). For any triangle, those three altitudes always intersect at exactly one point: the <u>orthocenter</u>. This is one of the many centers of a triangle. Other centers are the centroid, incenter, and circumcenter.

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Find the projection of u = &lt;–6, –7&gt; onto v = &lt;1, 1&gt; a. &lt;-13/2,-13/2&gt; b. &lt;39,91/2&gt; c. &lt;-13/1764,-13/17
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<em>Now;</em>

<em>Let's find the following</em>

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u . v = -6 -7 = -13

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<em>Substitute these values into equation (i) as follows;</em>

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proj_vu = \frac{-13}{2} [i + j]

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proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

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