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3 years ago

Please help me answer this

Mathematics

1 answer:

prohojiy [21]3 years ago

8 0

9514 1404 393

Answer:

z^11

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)(a^c) = a^(b+c)

$z^5\cdot z^6=z^{5+6}=\boxed{z^{11}}$

<em>Additional comment</em>

It might help you to think of an exponent as indicating repeated multiplication. It tells you how many times the factor is repeated. In this case, it means ...

$z^5\cdot z^6=(z\cdot z\cdot z\cdot z\cdot z)\cdot(z\cdot z\cdot z\cdot z\cdot z\cdot z)\\=z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z\cdot z = z^{11}$

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The following are score earned by 15 college students on a 20-point math quiz. (a) calculate the mean, median, and mode scores.

Softa [21]

Answer:

(a) 12.87; 14; 18; (b) median

Step-by-step explanation:

(a) Statistics

(i) Mean

The mean is the sum of all the data points divided by the number of points.

$\begin{array}{rcl}\text{Mean} & = & \dfrac{0 + 2 + 3 + 12 + 12 + 13 + 14 + 14 + 15 + 15 + 18 + 18 + 18 + 19 + 20}{15}\\\\& = & \dfrac{193}{15}\\\\& = & \mathbf{12.87}\\\end{array}$

(ii) Median

The median is the middle value in your list of observations.

0, 2, 3, 12, 12, 13, 14, 14, 15, 15, 18, 18, 18, 19, 20

Median = 14

(iii) Mode

The mode is the value that appears most often in your list of observations.

0, 2, 3, 12, 12, 13, 14, 14, 15, 15, 18, 18, 18, 19, 20

Mode = 18

(b) Most representative measure

The mean is dragged down by three low values. The median is the measure that is most representative of the data.

The histogram below shows the distribution of your data.

8 0

3 years ago

Complete the steps to factor the tens 30 x 40

Harlamova29_29 [7]

1,200 is the answer.

6 0

3 years ago

Read 2 more answers

The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 199 times. Here are the observed

Anton [14]

Answer with explanation:

An Unbiased Dice is Rolled 199 times.

Frequency of outcomes 1,2,3,4,5,6 are=28, 29, 47, 40, 22, 33.

Probability of an Event

$=\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}\\\\P(1)=\frac{28}{199}\\\\P(2)=\frac{29}{199}\\\\P(3)=\frac{47}{199}\\\\P(4)=\frac{40}{199}\\\\P(5)=\frac{22}{199}\\\\P(6)=\frac{33}{199}\\\\\text{Dice is fair}\\\\P(1,2,3,4,5,6}=\frac{33}{199}$

→→→To check whether the result are significant or not , we will calculate standard error(e) and then z value

$(e_{1})^2=(P_{1})^2+(P'_{1})^2\\\\(e_{1})^2=[\frac{28}{199}]^2+[\frac{33}{199}]^2\\\\(e_{1})^2=\frac{1873}{39601}\\\\(e_{1})^2=0.0472967\\\\e_{1}=0.217478\\\\z_{1}=\frac{P'_{1}-P_{1}}{e_{1}}\\\\z_{1}=\frac{\frac{33}{199}-\frac{28}{199}}{0.217478}\\\\z_{1}=\frac{5}{43.27}\\\\z_{1}=0.12$

→→If the value of z is between 2 and 3 , then the result will be significant at 5% level of Significance.Here value of z is very less, so the result is not significant.

$(e_{2})^2=(P_{2})^2+(P'_{2})^2\\\\(e_{2})^2=[\frac{29}{199}]^2+[\frac{33}{199}]^2\\\\(e_{2})^2=\frac{1930}{39601}\\\\(e_{2})^2=0.04873\\\\e_{2}=0.2207\\\\z_{2}=\frac{P'_{2}-P_{2}}{e_{2}}\\\\z_{2}=\frac{\frac{33}{199}-\frac{29}{199}}{0.2207}\\\\z_{2}=\frac{4}{43.9193}\\\\z_{2}=0.0911$