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kari74 [83]
3 years ago
11

Pls help will give brainilist

Mathematics
1 answer:
omeli [17]3 years ago
7 0

Answer: use search website

Step-by-step explanation: its good

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Mr. I does a job in x hours while Mr. L can do it in y hours. How much of the job could they do together if they were to work fo
dimulka [17.4K]

Answer: Work done by both of them in k hours is

\frac{k(x+y)}{xy}

Explanation:

Since we have given that

Number of hours Mr. I does a job = x hours

Number of hours Mr. L does a job = y hours

Work done by Mr. I is given by

\frac{1}{x}

Work done by Mr. L is given by

\frac{1}{y}

Work done if they do together is given by

\frac{1}{x}+\frac{1}{y}\\\\=\frac{x+y}{xy}

Work done if they work together for k hours is given by

\frac{x+y}{xy}\times k\\\\=\frac{k(x+y)}{xy}

Hence, work done by both of them in k hours is

\frac{k(x+y)}{xy}

3 0
3 years ago
Subtract the rational expression
malfutka [58]
The correct answer is B
6 0
3 years ago
Y=(1/2)^x +2. What is the horizontal asymptote of this function?
professor190 [17]
\lim_{x\to -\infty} \left(\frac{1}{2}\right)^x+2=\infty+2=\infty\\
\lim_{x\to \infty} \left(\frac{1}{2}\right)^x+2=0+2=2\\

There is one-sided horizontal asymptote y=2
6 0
4 years ago
Find they area of a regular hexagon with a side length of 10 inches
Vitek1552 [10]
A≈259.81in²

I hope this helped!!
3 0
3 years ago
For which value of theta is cot (theta) undefined?
sattari [20]

The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.


\cot(x) = \frac{\cos(x)}{\sin(x)}


Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.


Let's look at your option:


\sin(90^\circ) = 1, so the cotangent is defined here


\sin(180^\circ) = 0, so the cotangent is not defined here


\sin(270^\circ) = -1, so the cotangent is defined here


\sin(450^\circ) = \sin(360^\circ+90^\circ)=\sin(90^\circ) = 1, so the cotangent is defined here

6 0
3 years ago
Read 2 more answers
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