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zvonat [6]
3 years ago
7

. Explain the composition of the earth.

Chemistry
1 answer:
nadya68 [22]3 years ago
8 0

Answer: ​​The earth is made up of three different layers: the crust, the mantle and the core. This is the outside layer of the earth and is made of solid rock.

Explanation: hope this helps.

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Find the mass, in grams, of 3.758 mol CH4. ( show work )
vladimir2022 [97]

Answer:

The mass of CH4 is 60, 29 grams.

Explanation:

We use the weight of the atoms C and H for calculate the molar mass:

Weight of CH4= weight C+ 4 x weight H= 12,01 g/mol +4 x 1,008g/mol=

Weight of CH4 =16, 042 g/mol

1molCH4-----16, 042grams

3,758 mol CH4--X= (3,758 mol CH4 x 16, 042 grams)/1 mol CH4=60,285836 grams

5 0
3 years ago
1) The hydrocarbon C15 H32 burns to form carbon dioxide and water. Write the equation for the reaction.
Dahasolnce [82]

Explanation:

Ch4+heat=CO2.

Ans

It is not balanced equation if you want it say in comment

8 0
3 years ago
Zinc oxide helps protect the lifeguards from damaging UV sunlight. How does this cream protect from the UV rays of the Sun?
nadezda [96]
It reflects sunlight.  It's a physical barrier (in comparison to some sunscreens which are chemical blocks).  Sunlight is mostly white light and zinc oxide reflects white light
8 0
4 years ago
t 745 K, the reaction below has an equilibrium constant (Kc) of 5.00 × 102. H2 (g) + I2 (g) ⇌ 2 HI (g) If a mixture of 0.10 mol
spayn [35]

Answer : The concentration of HI (g) at equilibrium is, 0.643 M

Explanation :

The given chemical reaction is:

                        H_2(g)+I_2(g)\rightarrow 2HI(g)

Initial conc.    0.10        0.10      0.50

At eqm.        (0.10-x)  (0.10-x)   (0.50+2x)

As we are given:

K_c=5.00\times 10^2

The expression for equilibrium constant is:

K_c=\frac{[HI]^2}{[H_2][I_2]}

Now put all the given values in this expression, we get:

5.00\times 10^2=\frac{(0.50+2x)^2}{(0.10-x)\times (0.10-x)}

x = 0.0713  and x = 0.134

We are neglecting value of x = 0.134 because the equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.0713

The concentration of HI (g) at equilibrium = (0.50+2x) = [0.50+2(0.0713)] = 0.643 M

Thus, the concentration of HI (g) at equilibrium is, 0.643 M

8 0
4 years ago
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Luba_88 [7]

Answer:

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Explanation:

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