Answer:
Esterification reaction
Explanation:
When we have to go from an acid to an ester we can use the <u>esterification reaction</u>. On this reaction, an alcohol reacts with a carboxylic acid on acid medium to produce an ester and water. (See figure).
In this case, we need the <u>methyl ester</u>, therefore we have to choose the <u>appropriate alcohol</u>, so we have to use the <u>methanol</u> as reactive if we have to produce the methyl ester.
Answer:
The filter bed is cleaned by occasional backwashing ;-; im sorry if this isn't a great answer but I tried
Answer:
pressure of gas are constant describe the relationship between moles and temprature
Answer:
1) 17.5 mL
Explanation:
Hello,
In this case, the reaction between sulfuric acid and potassium hydroxide is:
![H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O](https://tex.z-dn.net/?f=H_2SO_4%2B2KOH%5Crightarrow%20K_2SO_4%2B2H_2O)
In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:
![2*n_{acid}=n_{base}](https://tex.z-dn.net/?f=2%2An_%7Bacid%7D%3Dn_%7Bbase%7D)
And in terms of concentrations and volumes:
![2*M_{acid}V_{acid}=M_{base}V_{base}](https://tex.z-dn.net/?f=2%2AM_%7Bacid%7DV_%7Bacid%7D%3DM_%7Bbase%7DV_%7Bbase%7D)
Thus, we solve for the volume of acid:
![V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL](https://tex.z-dn.net/?f=V_%7Bacid%7D%3D%5Cfrac%7BM_%7Bbase%7DV_%7Bbase%7D%7D%7B2%2AM_%7Bacid%7D%7D%20%3D%5Cfrac%7B35mL%2A1.5M%7D%7B2%2A1.5M%7D%20%5C%5C%5C%5CV_%7Bacid%7D%3D17.5mL)
Best regards.