Answer:
The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.
Explanation:
- To solve this problem, we use Clausius Clapeyron equation: ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂).
- The first case: P₁ = 1 atm = 760 torr and T₁ = 451.0 K.
- The second case: P₂ = <em>??? needed to be calculated</em> and T₂ = 61.5 °C = 334.5 K.
- ΔHvap = 48.8 KJ/mole = 48.8 x 10³ J/mole and R = 8.314 J/mole.K.
- Now, ln(P₁/P₂) = (ΔHvap / R) (1/T₁ - 1/T₂)
- ln(760 torr /P₂) = (48.8 x 10³ J/mole / 8.314 J/mole.K) (1/451 K - 1/334.5 K)
- ln(760 torr /P₂) = (5869.62) (-7.722 x 10⁻⁴) = -4.53.
- (760 torr /P₂) = 0.01075
- Then, P₂ = (760 torr) / (0.01075) = 70691.73 torr.
So, The vapor pressure of benzaldehyde at 61.5 °C is 70691.73 torr.
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Oxidation happens at the anode and reduction happens at the cathode.<span />
The potential of hydrogen pH of the solution with the given value of pOH to the nearest hundredth is 10.55.
What is pH of solution?
The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration [H+] of the given solution.
It is expressed as;
pH = -log[ H⁺ ]
Also,
pH + pOH = 14
Given that;
We simply substitute our values into the expression above.
pH + pOH = 14
pH + 3.45 = 14
pH = 14 - 3.45
pH = 10.55
Therefore, the potential of hydrogen pH of the solution with the given value of pOH to the nearest hundredth is 10.55.
Learn more about pH & pOH here: brainly.com/question/17144456
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