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LUCKY_DIMON [66]
3 years ago
7

How many anions are in 0.500 g of MgBr2

Chemistry
1 answer:
Oksana_A [137]3 years ago
4 0

<u>Given:</u>

Mass of MgBr2 = 0.500 g

<u>To determine:</u>

Number of anions in 0.500 g MgBr2

<u>Explanation:</u>

Molar mass of MgBr2 = 24 + 2 (80) = 184 g/mol

Moles of MgBr2 = 0.500 g/184 g.mol-1 = 0.00271 moles

Based on stoichiometry-

1 mole of MgBr2 has 1 mole of Mg2+ cations and 2 moles of Br- anions

Therefore, 0.00271 moles of MgBr2 will have: 2 * 0.00271 = 0.00542 moles of Br-

Now,

1 mole of Br- contains 6.023 * 10²³ anions

0.00542 moles of Br- contain: 0.00542 * 6.023*10²³ = 3.264*10²¹ anions

Ans: There are 3.264*10²¹ anions in 0.5 g of MgBr2


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3 years ago
Decreasing the temperature of the reaction 3H2 + N2 2NH3. In this reaction, the product absorbs heat. WHICH WAY WILL THE REACTIO
Alex

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the reaction will shift towards the “heat”—shifts to the left

Explanation:

To summarize:

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o If temperature decreases (removing heat), the reaction will shift towards the “heat” term and go in the

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a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte
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The absorbance reported by the defective instrument was 0.3933.

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True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

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T = true transmittance of the sample

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now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

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To know more about transmittance click here:

brainly.com/question/17088180

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3 0
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