We look at the tens place
20 is in the tens place
now look at the Ones place
6 is in the Ones place
If it is 5 or greater we round it to the next ten, if it is 4 or less we keep it the same
6 is greater than 5
The number will be rounded to 430
Answer:
50 hombres y 25 mujeres
Step-by-step explanation:
Sea m el número de hombres y w el número de mujeres.
El total es 75
Así; m + w = 75 •••••••• (i)
Además; 16% de m + 20% de w = 13
0,16 m + 0,2 w = 13
Multiplicar por 100
16m + 20w = 1300 ••••• (ii)
De i, m = 75-w 16 (75-w) + 20w = 1300
1200 - 16w + 20w = 1300
4w = 1300-1200
w = 100/4 w = 25
Recordar; w + m = 75
25 + m = 75
m = 75-25
m = 50
If $200 is the maximum a coach can spend on new shorts, and needs at least 15 shorts, then you could divide or use an inequality. first take the maximum number (200) and the minimum amount (15s) and use the minimum and maximum signs of knowledge to form an inequality. you should end up with 15s<200.
Answer: 1/4 full.
Step-by-step explanation:
The question is asking for how much gas will be left in the tank after 2/3 of the gas in the tank is used.
There is currently 3/4 of the tank remaining.
To find 2/3 of 3/4, you can multiply the fractions together.
Do this by multiplying both numerators and both denominators:
![\frac{2}{3} *\frac{3}{4} = \frac{2*3}{3*4} = \frac{6}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%20%2A%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cfrac%7B2%2A3%7D%7B3%2A4%7D%20%3D%20%5Cfrac%7B6%7D%7B12%7D)
Then, subtract 6/12 from 3/4. You can do this by simplifying the first fraction to 2/4 (divide both the numerator and denominator by 3).
3/4 - 2/4 = 1/4
There will be 1/4 of the tank left.
B, because the mid segment is half the length of the third side