The difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11
<h3>How to determine the notation</h3>
Given the expression
(5. 29 × 10^11) - (3. 86 × 10 ^11)
First, find the common factor
10^11 ( 5. 29 - 3. 86)
Then substract the values within the bracket
10^11 (1. 43)
Multiply with the factor, we have
⇒1. 43 × 10^11
Thus, the difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11
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The equation that fits is y=3x+1
Answer:
224
Step-by-step explanation:
i think you would do 16 X 2 and then times that by 7 which would give the answer as 224
Answer:
10
Step-by-step explanation:
By Pythagoras' Theorem:
16 + r = √(24^2 + r^2)
(16 + r)^2 = 24^2 + r^2
256 + 32r + r^2 = 576 + r^2
32r = 320
r = 10
