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3 years ago

10

Which type of function is shown in the table below?

1 answer:

Hunter-Best [27]3 years ago

3 0

it's not a function unless it's something different

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Need help with 3,4,5,6

LuckyWell [14K]

The answers are:
3:d
4:c
5:b
6:c Note: I am not 100% sure.

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3 years ago

Plot the x- and y-intercepts of function f(x)=x

katrin2010 [14]

Because f(x)=x, goes through origin. So x and y -intercept are one point (0,0).

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3 years ago

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A bag of marbles has 5 red, 2 blue, and 3 green marbles. A marble is randomly selected. What is the probability AS A DECIMAL tha

loris [4]

Answer:

0.25 Hope this helps :)

Step-by-step explanation:

You add the 5 red and 3 green

8 Mables besides blue

so that's 2/8

simplified 1/4

1/4=0.25

8 0

3 years ago

A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4

vlabodo [156]

Answer:

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

Step-by-step explanation:

Bernoulli's equation,

$P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2$

P₁ = P₂= atmospheric presser

$\rho$ = density

$\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2$ [since P₁ = P₂]

$\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)$

$\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2$

$\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2$

$\Rightarrow v^2_2- v^2_1=2g h$ [ $h_1-h_2=h$ ]

Here $v_1\approx 0$

$\Rightarrow v^2_2=2g h$

$\therefore v_2=\sqrt {2gh$

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole $v_2$ = $\sqrt {2\times 9.8\times 10.4}$ m/s

=14.28 m/s.

Given, the rate of flow from the leak is $2.53\times 10^{-3}$ $m^3/min$

$=\frac{2.53\times 10^{-3}}{60}$ $m^3/s$

Let the diameter of the hole be d.

Then the cross section area of the hole is $=\pi (\frac d2)^2$

We know that,

The rate of flow = Cross section area × speed

$\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28$

$\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}$

$\Rightarrow d= 1.94 \times 10^{-3}$

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

4 0

4 years ago

L M A O L M A O L M A O L M A O

kiruha [24]

Not sure if this is a question im confused

6 0

3 years ago

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