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IgorC [24]
3 years ago
9

For the function defined by the equation y=3/2x+6 what is the output when the input is -10

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0
Y=-9
Input is basically your x value so output is basically your y value
So plug in -10 for x
Y=3/2(-10)+6
Y=-15+6
Y=-9
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Choose the point slope form of the equation below that represents the line that passes through the points (-6,4) and (2,0) Y+6=2
olchik [2.2K]

Answer:

you would need to see which one adds up or just an answer out in the wen then see what you get from there if not go find another way

Step-by-step explanation:

5 0
2 years ago
Simply<br> tan 45°. sin 30° - cot 45°/sec 60°​
dusya [7]

If we want to write the given four numbers in another form, we can write it like this;

tan45=sin45/cos45=1

sin30=sin(\frac{\pi }{2}-60 )=cos60=\frac{1}{2}

cot45=cos45/sin45=1

sec60=1/cos60=\frac{1}{1/2} =2

Now let's rewrite the given expression and get the result.

(tan45.sin30)-(cot45/sec60)=(1.\frac{1}{2})-(\frac{1}{2} )=0

5 0
1 year ago
Read 2 more answers
Fraction that is equivalent to but different from 4/13​
dem82 [27]

Answer:

8/26

Step-by-step explanation:

All you have to do is multiply the numerator and denominator with the same number. For example, I did 2. 4x2=8, and 2x13=26.

4 0
3 years ago
Over what interval is the function in this graph decreasing?
lys-0071 [83]

Answer:

The answer is D.

Step-by-step explanation:

8 0
3 years ago
Please help me with these two math problems that I do not quite understand. This is urgent!
g100num [7]

Answer:

1)a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19

2) a_{10}=4+8(10-1)\Rightarrow a_{10}=76

Step-by-step explanation:

1) To write an Arithmetic Sequence, as an Explicit Term, is to write a general formula to find any term for this sequence following this pattern:

a_{n}=a_{1}+d(n-1)\Rightarrow \left\{\begin{matrix}a_{n}=n^{th}\: term\\a_1=1st \: term \\d=\: difference\\n=n^{th}\, term\end{matrix}\right.

<em>"Write an explicit formula for each explicit formula A(n)=-1+(n-1)(-2)"</em>

This isn't quite clear. So, assuming you meant

Write an explicit formula for each term of this sequence A(n)=-1+(n-1)(-2)

As this A(n)=-1+(n-1)(-2)  is already an Explicit Formula, since it is given the first term a_{1}=-1 the common difference d=-2 let's find some terms of this Sequence through this Explicit Formula:

a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19

2) (4,12,20,28, ..) In this Arithmetic Sequence the common difference is 8, the first term value is 4.

Then, just plug in the first term and the common difference into the explicit formula:

a_{10}=4+8(10-1)\Rightarrow a_{10}=76

6 0
2 years ago
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