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Marysya12 [62]
2 years ago
9

A 98% confidence interval is found to be (32,46). What is the margin of error ?

Mathematics
1 answer:
solong [7]2 years ago
3 0

Using <em>confidence interval concepts</em>, it is found that the margin of error is of 7.

  • A confidence interval has the format (a,b).
  • The <em>margin of error</em> is <u>half the difference between the two bounds</u>, that is:

M = \frac{b - a}{2}

In this problem, the interval is (32, 46), hence b = 46, a = 32, and the <em>margin of error</em> is:

M = \frac{46 - 32}{2} = 7

The margin of error is of 7.

A similar problem is given at brainly.com/question/25704940

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So, 37.5% of the values will lie above the mean and 37.5% of the values lie below the mean.

In a Z-table, mean is located at the center of the data. So the position of the mean is at 50% of the data. So the position of point 37.5% above the mean will be located at 50 + 37.5 = 87.5% of the overall data

Similarly position of the point 37.5% below the mean will be located at 
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From the z table, we can find the z value for both these points. 12.5% converted to z score is -1.15 and 87.5% converted to z score is 1.15.

Using these z scores, we can find the values which contain 75% of the values about the mean.

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