Question

A 98% confidence interval is found to be (32,46). What is the margin of error ?

Answer 1

Using confidence interval concepts, it is found that the margin of error is of 7.

• A confidence interval has the format (a,b).

• The margin of error is half the difference between the two bounds, that is:

$M = \frac{b - a}{2}$

In this problem, the interval is (32, 46), hence $b = 46, a = 32$, and the margin of error is:

$M = \frac{46 - 32}{2} = 7$

The margin of error is of 7.

A similar problem is given at brainly.com/question/25704940