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DENIUS [597]
2 years ago
14

In order to clear out room for new merchandise, James decided to mark down some of the items for sale in his electronics store.

He marked down DVD players by 36%, and he marked down stereo tuners by 22%. If DVD players cost $41. 60 after the markdown and stereo tuners cost $69. 42 after the markdown, which item’s price was reduced by more, and by how many dollars more was it reduced? Round all dollar values to the nearest cent. A. The DVD player’s price was reduced by $3. 82 more than the stereo tuner’s price. B. The DVD player’s price was reduced by $27. 82 more than the stereo tuner’s price. C. The stereo tuner’s price was reduced by $0. 29 more than the DVD player’s price. D. The stereo tuner’s price was reduced by $27. 53 more than the DVD player’s price.
Mathematics
1 answer:
masya89 [10]2 years ago
4 0

The correct answer is A, as the DVD player's price was reduced by $ 3.82 more than the stereo tuner's price.

In order to clear out room for new merchandise, James decided to mark down some of the items for sale in his electronics store, and he marked down DVD players by 36%, and he marked down stereo tuners by 22%, if DVD Players cost $ 41.60 after the markdown and stereo tuners cost $ 69.42 after the markdown.

To determine which item's price was reduced by more, and by how many dollars more was it reduced, the following calculation must be performed:

  • 100 - 36 = 64
  • 64 = 41.60
  • 100 = X
  • 100 x 41.60 / 64 = X
  • 4160/64 = X
  • 65 = X
  • 65 - 41.60 = 23.40

  • 100 - 22 = 78
  • 78 = 69.42
  • 100 = X
  • 69.42 x 100/78 = X
  • 6942/78 = X
  • 89 = X
  • 89 - 69.42 = 19.58

Therefore, the DVD player's price was reduced by $ 3.82 more than the stereo tuner's price.

Learn more about maths in brainly.com/question/18629331

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