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olya-2409 [2.1K]
3 years ago
7

Which of the following transformations represents an isometry?

Mathematics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Isometry only includes, rotation, translation, and reflection.

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the ages of two friends Sunaina and Tanish are differ by 2 years sunaina's father is twice as old as Sunaina and Tanisha is twic
nikklg [1K]

Let S represent Sunaina's age.

Let T represent Tanish's age.

So 2S - T/2 = 40, 4S - T = 80.

Either S - T = 2 or T - S = 2. Let's try both cases.

Either 3S = 78 or 3S = 82.

Since 82 is not a multiple of 3, S = 26.

So Sunaina is 26 years old and Tanish is 24 years old.

4 0
3 years ago
What is a35 for the arithmetic sequence presented in the table below?
Kryger [21]

Answer: choice B) a35 = -118

=====================================================

Explanation:

When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get

an = a1+d(n-1)

32 = a1+d(5-1)

32 = a1+4d

Solve for a1 by subtracting 4d from both sides

a1 = 32-4d

We'll plug this in later

Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula

an = a1+d(n-1)

7 = a1 + d(10-1)

7 = a1+9d

Now substitute in the equation in which we solved for a1

7 = a1+9d

7 = 32-4d+9d ... replace a1 with 32-4d

7 = 32+5d

5d = 7-32

5d = -25

d = -25/5

d = -5

This tells us that we subtract 5 from each term to get the next term.

Use this d value to find a1

a1 = 32-4d

a1 = 32-4*(-5)

a1 = 32+20

a1 = 52

The first term is 52

--------------

The nth term formula is therefore

an = 52 + (-5)(n-1)

which simplifies to

an = -5n + 57

To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.

--------------

Replace n with 35 to find the 35th term

an = -5n + 57

a35 = -5(35) + 57

a35 = -175 + 57

a35 = -118

7 0
3 years ago
A catering service offers
Fiesta28 [93]

Answer:

There are 52920 ways to do the banquet

Step-by-step explanation:

* Lets revise the combination to solve this problem

- A combination is a collection of the objects where the order

 doesn't matter

- The order is not important in this problem, so we can use the  

  combination nCr to find how many ways can this done

* Lets solve the problem

- A catering service offers 6 appetizers, 7 main courses, 10 desserts.

- A customer is to select 5  appetizers,  4  main courses, 5  desserts

 for a banquet

∵ We want to select  5  appetizers from 6

∴ There are 6C5 ways to chose the appetizers

∵ 6C5 = 6

∴ There are 6 ways to chose the appetizers

∵ We want to select  4  main courses from 7

∴ There are 7C4 ways to chose the main courses

∵ 7C4 = 35

∴ There are 35 ways to chose the main courses

∵ We want to select  5  desserts from 10

∴ There are 10C5 ways to chose the desserts

∵ 10C5 = 252

∴ There are 252 ways to chose the desserts

- To find the number of ways to do the banquet multiply all the

  answers above

∵ The total ways = 6C5 × 7C4 × 10C5

∴ The total ways = 6 × 35 × 252 = 52920

* There are 52920 ways to do the banquet

5 0
3 years ago
at a sport banquett 8 guests are seated at each of the 15 tables how many guests (x) are seated at the table
Novosadov [1.4K]

Answer:

120

Step-by-step explanation:

15x8=120 so that the answer

7 0
4 years ago
Read 2 more answers
Add or subtract each expression.Simplify your final answer show all work.
Elan Coil [88]
1) 2x-1 or x=1/2
2) 5a-16 or a=16/5
8 0
4 years ago
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