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3 years ago

A rectangle that is 2 inches by 3 inches has been scaled by a factor of 7.

Mathematics

1 answer:

loris [4]3 years ago

6 0

Answer:

$New\ Lengths = (14,21)$

$New\ Scale\ Factor = \frac{1}{7}$

Step-by-step explanation:

Given

Rectangle:

Length = 2 in

Width = 3 in

Scale Factor = 7

Solving (a):

The side lengths of the new scale is calculated as follows;

New Lengths = Old Lengths * Scale Factor

$New\ Lengths = (2,3) * 7$

$New\ Lengths = (2 * 7,3* 7)$

$New\ Lengths = (14,21)$

Solving (b): To go back to the original length

Given that the initial scale factor is 7;

The new scale factor is the reciprocal of the old factor;

Hence;

$New\ Scale\ Factor = \frac{1}{7}$

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geniusboy [140]

Answer:

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Step-by-step explanation:

So the question here is asking you to use the quadratic formula which is expressed as: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\$

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So using the equation you gave: $0=x^2-5x-1$

We can identify the following values: a=1, b=-5, c=-1

Btw the equation explicitly write "1" as the coefficient of x, but since it's not provided it's implied that it's 1.

So plugging in the known values, we get the following equation:

$x=\frac{5\pm\sqrt{(-5)^2-4(1)(-1)}}{2(1)}\\\\x=\frac{5\pm\sqrt{25+4}}{2}\\\\x=\frac{5\pm\sqrt{29}}{2}\\\\x=2.5+\frac{\sqrt{29}}{2}\\\\x=2.5-\frac{\sqrt{29}}{2}$

The last step just consists of taking the + and - solution, and since it asks for exact solutions you leave the 29 under the radical, and you don't approximate. There is no further simplification that can be done here.

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kvv77 [185]

Answer:

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Answer:

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