Answer: 56 large cars and 86 small cars.
Step-by-step explanation:
Let's call:
: the number of large cars.
: the number of small cars.
Then, you can set up the following system of equations:

You can use the Elimination Method:
- Multiply the first equation by -4.0
- Add both equations.
- Solve for l.

≈
Substitute
into one of the original equations and solve for <em>s:</em>
<em> </em>
If the problem is supposed to read (4^33*8^37)/(4^15*8^21), then...
(4^33*8^37)/(4^15*8^21) = (4^33/4^15)*(8^37/8^21)
(4^33*8^37)/(4^15*8^21) = 4^(33-15)*8^(37-21)
(4^33*8^37)/(4^15*8^21) = 4^18*8^16
Answer: Choice A) 4^18*8^16
False
uiergujhgbsegbsi;gs io rgoirti; erio;terh i ioer;te ith hirh;;
Answer:
The y intercept, (0,400) represents the amount of money the radio station originally had. The x-intercept, (8,0), represents the amount of weeks it will take for the radio station to have $0 left.
Step-by-step explanation: