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3 years ago

Help me..it has to be rounded to the tenths

Mathematics

2 answers:

klio [65]3 years ago

7 0

Answer:

10.2 cm²

Step-by-step explanation:

The area (A) of a regular hexagon is

A = $\frac{1}{2}$ × perimeter × apothem

Perimeter = 6 × 2 = 12 cm ( hexagon has 6 sides ), hence

A = 0.5 × 12 × 1.7 = 6 × 1.7 = 10.2 cm²

DaniilM [7]3 years ago

3 0

Answer:

10.2cm^2

Step-by-step explanation:

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3 years ago

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PLEASEEEEEE HELPPPPP!!

DaniilM [7]

Answer:

y-b+am/m

Step-by-step explanation:

y-b=m(x-a)

y-b=MX-ma

mx=y-b+ma

x=y-b+ma/m

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3 years ago

WHAT IS X³-27 SIMPLIFIED

Eduardwww [97]

Answer:

It is (x - 3)³ - 9x(3 - x)

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

$= {x}^{3} - {3}^{3}$

From trinomial expansion:

${(x - y)}^{3} = (x - y)(x - y)(x - y) \\$

open first two brackets to get a quadratic equation:

${(x - y)}^{3} = ( {x}^{2} - 2xy + {y}^{2} )(x - y)$

expand further:

${(x - y)}^{3} = {x}^{3} - y {x}^{2} - 2y {x}^{2} + 2x {y}^{2} + x {y}^{2} - {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3x {y}^{2} - 3y {x}^{2} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3xy(y - x) \\ \\ { \boxed{( {x}^{3} - {y}^{3} ) = {(x - y)}^{3} - 3xy(y - x)}}$

take y to be 3, then substitute:

$( {x}^{3} - 3^3) = {(x - 3)}^{3} - 9x(3 - x)$

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3 years ago

Simplify the expression. A) 8^4•8^9

OlgaM077 [116]

Answer:

${8}^{13}$

Step-by-step explanation:

${8}^{4} \times {8}^{9} \\ {8}^{4 + 9} \\ {8}^{13} \\ = 5.497558139 \times 10 ^{11}$

Hope this helps you.

Let me know if you have any other questions :-)

7 0

3 years ago

What is m∠Q ?

ddd [48]

Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.

Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A

Applying that here:

40^2 = 32^2 + 64^2 - 2(32)(64)cos Q

Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.

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3 years ago

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