Answer:
1st graph is Y=1x+0
2nd Graph is Y=-2/1x + 0
Step-by-step explanation:
Your slope is 1 for the 1st graph
Your slope is -2/1 for the second graph
Answer:
infinitely many solutions
1) cscΘ = - 2
=>
1
------ = - 2
sinΘ
=> sinΘ = - 0.5 => Θ is in the third and fourth quadrant
=> Θ = 180° + 30° = 210°
and Θ = 360° + 30° = 330°
2) tan Θ = √3
=> Θ = 60° and Θ = 180° + 60° = 240°
We are going to make the product step by step.
We have:
(6 + 5i) * (3-7i)
Multiplying:
((6) * (3)) + ((6) * (- 7i)) + ((5i) * (3)) + ((5i) * (- 7i))
Rewriting:
18 - 42i + 15i - 35i ^ 2
18 - 42i + 15i - 35 * (- 1)
18 - 42i + 15i + 35
53 - 27i
Answer:
the product of and (6 + 5i) and (3-7i) is:
53-27i
Answer:
Slope-int form: y = 3x+5
Standard form: y - 3x = 5.
Step-by-step explanation:
(reminder: slope-intercept form is expressed as y=mx+b, and standard form is expressed as ax+bx=c.)
Since the slope is 3, the coefficient of x is also 3, which makes the equation y=3x.
But the y coordinate of the equation at x = -2 is -6, so we need to add 5 to the end of the equation, leaving you with:
y=3x+5.
To convert it to standard form, subtract 3x from both sides:
y - 3x = 5.
I hope this helped you.
