The answer is 225
I got that by mulitplying .15 by 1500
        
                    
             
        
        
        
Answer:
y-b+am/m
Step-by-step explanation:
y-b=m(x-a)
y-b=MX-ma
mx=y-b+ma
x=y-b+ma/m
 
        
             
        
        
        
Answer:
<u>It</u><u> </u><u>is</u><u> </u><u>(</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>)</u><u>³</u><u> </u><u>-</u><u> </u><u>9</u><u>x</u><u>(</u><u>3</u><u> </u><u>-</u><u> </u><u>x</u><u>)</u>
Step-by-step explanation:
Express 27 in terms of cubes, 27 = 3³:

From trinomial expansion:

open first two brackets to get a quadratic equation:

expand further:

take y to be 3, then substitute:

 
        
             
        
        
        
Answer:

Step-by-step explanation:

Hope this helps you.
Let me know if you have any other questions :-)
 
        
             
        
        
        
Unlike the previous problem, this one requires application of the Law of Cosines.  You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines:  a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
                           40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math.  Solve for cos Q, and then find Q in degrees and Q in radians.