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2 years ago

What is the applications of echo

Physics

2 answers:

Reil [10]2 years ago

8 0

English:

Applications of echoes

Echoes are used by bats, dolphins and fisherman to detect an object / obstruction. They are also used in SONAR (Sound navigation and ranging) and RADAR(Radio detection and ranging) to detect an obstacle.

Tagalog:

Mga aplikasyon ng dayandang

Ang mga dayandang ay ginagamit ng mga paniki, dolphin at mangingisda upang makita ang isang bagay / sagabal. Ginagamit din ang mga ito sa SONAR (Sound navigation and ranging) at RADAR(Radio detection and ranging) upang makita ang isang balakid.

Explanation:

Sana makatulog ❤️

shepuryov [24]2 years ago

5 0

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When a sound wave is produced in air, some of it is absorbed after hitting with a reflector while some of the sound wave is reflected back to the listener. This reflected sound is called echo.

Applications of Echo:

Since bats cannot see from their eyes, so they use the technique of echolocation to locate their ways. Bats can understand from the reflected sound if there is any object before it. It hunts its prey by using this technique.
This technique is also used to find the depth of sea or distance of submarines
It also helps to estimate the distance or hills and mountains.
This technique is also very helpful in the medical field as well. Doctors used this phenomenon in cardiography, sonogram and many other medical diagnosis.

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A mass m = 3.9 kg hangs from a massless string wrapped around a uniform cylinder with mass Mp = 10.53 and radius R= 0.96 m. The

luda_lava [24]

Answer:

the rotational inertia of the cylinder = 4.85 kgm²

the mass moved 7.942 m/s

Explanation:

Formula for calculating Inertia can be expressed as:

$I =\frac{1}{2}mR^2$

For calculating the rotational inertia of the cylinder ; we have;

$I = \frac{1}{2}m_pR^2$

$I = \frac{1}{2}*10.53*(0.96)^2$

$I=5.265*(0.96)^2$

$I=4.852224$

I ≅ 4.85 kgm²

mg - T ma and RT = I ∝

T = $\frac{Ia}{R^2}$

$a = \frac{g}{1+\frac{I}{mR^2}}$

$a = \frac{9.8}{1+\frac{4.85}{3.9*(0.96)^2}}$

a = 4.1713 m/s²

Using the equation of motion

$v^2 = u^2+2as \\ \\ v^2 = 2as \\ \\ v = \sqrt{2*a*s} \\ \\ v= \sqrt{2*4.1713*7.56} \\ \\ v = 7.942 \ m/s$

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2 years ago

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Answer:

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Explanation:

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2 years ago

Discuss the factors that are used to determine power.

True [87]

<span>The factors that are used to determine power are:
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3 years ago

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Dos cargas puntuales están fijas en el eje x: q1 = 6.0µC está en el origen, O, con x1 = 0.0 cm, y q2 = –3.0 µC está situada en e

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Answer:

E_total = 1.30 10¹⁰ C / m²

Explanation:

The intensity of the electric field is

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E_total = E₁ + E₂

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E_total = 9 10⁹ / (4 10⁻²)² (6.0 10⁻⁶ +3.0 10⁻⁶)

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2 years ago

How can scientific phenomena be used in design?

Alex73 [517]

I’m not really sure I’m sorry

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2 years ago

What is the applications of echo​

What is the applications of echo