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Dimas [21]
2 years ago
8

What is the applications of echo​

Physics
2 answers:
Reil [10]2 years ago
8 0

English:

Applications of echoes

Echoes are used by bats, dolphins and fisherman to detect an object / obstruction. They are also used in SONAR (Sound navigation and ranging) and RADAR(Radio detection and ranging) to detect an obstacle.

Tagalog:

Mga aplikasyon ng dayandang

Ang mga dayandang ay ginagamit ng mga paniki, dolphin at mangingisda upang makita ang isang bagay / sagabal. Ginagamit din ang mga ito sa SONAR (Sound navigation and ranging) at RADAR(Radio detection and ranging) upang makita ang isang balakid.

Explanation:

Sana makatulog ❤️

shepuryov [24]2 years ago
5 0

\huge\tt{{\gray{ANSWER:}}}

When a sound wave is produced in air, some of it is absorbed after hitting with a reflector while some of the sound wave is reflected back to the listener. This reflected sound is called echo.

Applications of Echo:

  1. Since bats cannot see from their eyes, so they use the technique of echolocation to locate their ways. Bats can understand from the reflected sound if there is any object before it. It hunts its prey by using this technique.
  2. This technique is also used to find the depth of sea or distance of submarines
  3. It also helps to estimate the distance or hills and mountains.
  4. This technique is also very helpful in the medical field as well. Doctors used this phenomenon in cardiography, sonogram and many other medical diagnosis.
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calculate the efficiency of a light bulb that had an input of 400 j transfers 100j as a light and 300j as heat.​
beks73 [17]
Efficiency = useful energy out / total energy in x 100
= 100/400 x 100
=0.25 x 100
= 25%

25%
6 0
2 years ago
What is the resistance of a 600 W kettle that draws a current of 5.0 A? please answer with steps
lukranit [14]
P=I^2 *R

600 =5.0^2 *R

R=24

Answer: 24 ohms

I hope it’s correcttttttt...

5 1
2 years ago
Um objeto de 4cm de altura está a 30cm de um espelho côncavo, cujo raio de curvatura tem valor absoluto de 20cm.
Shkiper50 [21]

a) The distance of the image from the mirror is 15 cm

b) The size of the image is -2 cm (inverted)

Explanation:

a)

We can solve this first part of the problem by applying the mirror equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For a mirror, the focal length is half the radius of curvature, R:

f=\frac{R}{2}

For this mirror, R = 20 cm, so its focal length is

f=\frac{20}{2}=+10 cm (positive for a concave mirror)

Here we also know:

p = 30 cm is the distance of the object from the mirror

So, by applying the equation, we can find q:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{10}-\frac{1}{30}=\frac{1}{15} \rightarrow q = 15 cm

b)

We can solve this part by using the magnification equation:

M=-\frac{y'}{y}=\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

q = 15 cm

p = 30 cm

y = 4 cm

Solving for y', we find the size of the image:

y'=-y\frac{q}{p}=-(4)\frac{15}{30}=-2 cm

and the negative sign means that the image is inverted.

#LearnwithBrainly

6 0
3 years ago
9. A student walks 2 km in 30 minutes. What
Alina [70]

Answer:

4km/hr

Explanation:

There are 60 minute in an hour. If you divided 60 by 30 minutes you’d get 2. 2x 2km is 4km and 30x 2 is 60/an hour

8 0
2 years ago
Why are electromagnets more useful than permanent magnets in many
Likurg_2 [28]

Answer: Electromagnets can be turned on and off by controlling the current

Explanation:

5 0
2 years ago
Read 2 more answers
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