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2 years ago

HELP ME PLEASE IM DESPERATE Many inland areas around Florida contain extinct marine fossils.

Physics

1 answer:

chubhunter [2.5K]2 years ago

8 0

Answer:b

Explanation:

thats what my teacher said

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Automobile traveling at 65 mph constant on the road described below. Find rate at which radar must rotate when theta = 15 deg. A

Finger [1]

Answer:

The rate at which radar must rotate is 0.335 rad/s.

Explanation:

Given that,

Velocity = 65 m/h = 29.0576 m/s

Angle = 15°

Suppose, the radius given by

$r=(100\cos2\theta)\ m$

We need to calculate the rate at which radar must rotate

Using formula of linear velocity

$v=r\omega$

$\omega=\dfrac{v}{r}$

Where, v = velocity

r = radius

Put the value into the formula

$\omega=\dfrac{29.0576}{100\cos30}$

$\omega=0.335\ rad/s$

Hence, The rate at which radar must rotate is 0.335 rad/s.

3 0

3 years ago

if a kid is practicing for a play and there is an auditorium of loud people that are shouting, and he screams, he hears and echo

Vilka [71]

Because the sound waves are being observed by the people that are there and it is not empty as in an empty place the sound waves will come back to you.

5 0

3 years ago

A man pushes down on a lever with 45 N and the lever moves 1.5 meters. The other end of the lever lifts a 87.6 N box .4 meters.

AysviL [449]

The input work = Force x distance
So I/P = 45 x 1.5 = 67.5 N.m

The output work = Force x distance
So, O/P = 87.6 x 0.4 = 35.04 N.m

Efficiency = (output work / Inputwork) x 100
= ( 35.04/67.5) x100

Efficiency = 51.91 %

4 0

3 years ago

¿Qué es una onda electromagnética?

Leya [2.2K]

Answer:

Son aquellas ondas que no necesitan un medio material para propagarse. Incluyen, entre otras, la luz visible y las ondas de radio, televisión y telefonía. Todas se propagan en el vacío a una velocidad constante, muy alta (300 0000 km/s) pero no infinita.

3 0

3 years ago

The specific heat of water in its solid phase (ice) is 2090 J/(kg K), while in the liquid phase (water) its specific heat is 419

oee [108]

Answer:

d. 149 ⁰C.

Explanation:

Given;

mass of the block of ice, m = 2 kg

specific heat capacity of the ice, C = 2090 J/(kgK)

initial temperature of the ice, t₁ = -90 ⁰C

heat added to the ice, H = 1,000,000 J

let the final temperature of the ice = t₂

The final temperature of the ice after adding the heat is calculated as follows;

$H = mC_{ice} \Delta t\\\\H = mC_{ice} (t_2 - t_1)\\\\1,000,000 = 2 \times 2090 \times (t_2 - (-90))\\\\1,000,000 = 4,180(t_2 +90)\\\\1,000,000 = 4,180t_2 + 376,200\\\\1,000,000 - 376,200 = 4,180t_2\\\\623,800 = 4,180 t_2\\\\t_2 = \frac{623,800}{4,180} \\\\t_2 = 149 \ ^0C$

Therefore, the new temperature of the water is 149 ⁰C.

4 0

2 years ago