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Dovator [93]
4 years ago
15

Consider the reaction X mc022-1.jpg Y + 2Z . If the molar solubility of X is multiplied by 2, the value of Ksp will be multiplie

d by
Physics
1 answer:
Alex777 [14]4 years ago
4 0
X -> Y + 2Z

So there are 2 different particles. 1 mol of X produces 1 mol of Y and 2 moles of Z.

Kps = [Y] [Z]^2

We will call “s” (solubility) the molarity of X

So the molarity of Y+ is also “s” (same number)

And the molarity of Z is “2s” (twice as much)

Kps = s*(2s)^2 = s*4s^2=4s^3

If s is multiplied by 2:

Kps = 4*(2s)^3=4*2^3*s^3=4*8*s^3

So Kps is multiplied by 8.

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A 150 kg uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. Calculate the magn
xenn [34]

Answer:

T = 2010 N

Explanation:

m = mass of the uniform beam = 150 kg

Force of gravity acting on the beam at its center is given as

W = mg

W = 150 x 9.8

W = 1470 N

T = Tension force in the wire

θ = angle made by the wire with the horizontal =  47° deg

L = length of the beam

From the figure,

AC = L

BC = L/2

From the figure, using equilibrium of torque about point C

T (AC) Sin47 = W (BC)

T L Sin47 = W (L/2)

T Sin47 = W/2

T Sin47 = 1470

T = 2010 N

6 0
3 years ago
A 5 kg bowling ball travelling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1
Ilia_Sergeevich [38]

Answer:

  1.5 m/s

Explanation:

Conservation of momentum means the momentum of the system before the collision is the same as after.

The before, after momentum of each ball is ...

  5 kg ball: (5 kg)(2 m/s), (5 kg)(-1 m/s)

  10 kg ball: (10 kg)(0 m/s), (10 kg)(v)

The sum of the "before" products is the same as the sum of the "after" products:

  (5 kg)(2 m/s) +0 = (5 kg)(-1 m/s) +(10 kg)v

  (10 +5) kg·m/s = (10 kg)·v . . . . . add (5 kg)(1 m/s) to both sides

  v = (15 kg·m/s)/(10 kg) = 1.5 m/s

The speed of the larger ball will be 1.5 m/s. Its direction of motion will be the opposite of that of the 5 kg ball after the collision.

7 0
3 years ago
What type of wave does NOT need matter to carry energy? *
Blababa [14]

Answer:

I guess sound wave I s gonna be d right answer

Explanation:

cos sound doesnt has weight and occupies space

3 0
4 years ago
How much energy is transported across a
irina1246 [14]

Explanation:

Let us assume that Z is the energy transported across an area of 1.00 cm^{2} per hour by an electromagnetic wave with an r.m.s speed of 21.5 V/m.

Therefore, first we will calculate the current as follows.

                  I = \frac{E_{rms^{2}}}{c \times \mu_{o}}

                    = \frac{10^{-4} \times 3600 \times (21.5)^{2}}{3 \times 10^{8} \times 4 \times 3.14 \times 10^{-7}}

                    = 0.441 J

Therefore, we can conclude that 0.441 J energy is transported across a given EM wave.

4 0
3 years ago
Describe the steps in solving the problem below.
12345 [234]

The velocity of the red cart after the collision is 2 m/s

From the law of conservation of momentum, initial momentum of system = final momentum of system.

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.

Substituting the values of the variables into the equation, we have,

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄

4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s

16 kgm/s + 0 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s - 8 kgm/s =  (4 kg)v₃

(4 kg)v₃ = 8 kgm/s

Divide both sides by 4 kg, we have

v₃ = 8 kgm/s ÷ 4 kg

v₃ = 2 m/s

The velocity of the red cart after the collision is 2 m/s.

Learn more about conservation of momentum here:

brainly.com/question/7538238

3 0
3 years ago
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