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Dovator [93]
4 years ago
15

Consider the reaction X mc022-1.jpg Y + 2Z . If the molar solubility of X is multiplied by 2, the value of Ksp will be multiplie

d by
Physics
1 answer:
Alex777 [14]4 years ago
4 0
X -> Y + 2Z

So there are 2 different particles. 1 mol of X produces 1 mol of Y and 2 moles of Z.

Kps = [Y] [Z]^2

We will call “s” (solubility) the molarity of X

So the molarity of Y+ is also “s” (same number)

And the molarity of Z is “2s” (twice as much)

Kps = s*(2s)^2 = s*4s^2=4s^3

If s is multiplied by 2:

Kps = 4*(2s)^3=4*2^3*s^3=4*8*s^3

So Kps is multiplied by 8.

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Two parallel 3.0-meter long wires conduct current. The current in the top wire is 12.5 A and flows to the right. The top wire fe
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Complete question:

Two parallel 3.0-meter long wires conduct current. The current in the top wire is 12.5 A and flows to the right. The top wire feels a repulsive force of 2.4 x 10^-4 N created by the interaction of the 12.5 A current and the magnetic field created by the bottom current (I). Find the magnitude and direction of the bottom current, if the distance between the two wires is 40cm.

Answer:

The bottom current is 12.8 A to the right.

Explanation:

Given;

length of the wires, L = 3.0 m

current in the top wire, I₁ = 12.5 A

repulsive force between the two wires, F = 2.4 x 10⁻⁴ N

distance between the two wires, r = 40 cm = 0.4 m

The repulsive force between the two wires is given by;

F = \frac{\mu_oI_1I_2L}{2\pi r}\\\\I_{2} = \frac{2F\pi r}{\mu_oI_1L}

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I₂ is the bottom current

The direction of the bottom current must be in the same direction as the top current since the force between the two wires is repulsive.

I_{2} = \frac{2F\pi r}{\mu_oI_1L}\\\\I_{2} = \frac{2(2.4*10^{-4})(\pi)(0.4)}{(4\pi*10^{-7})(12.5)(3)}\\\\I_{2} = 12.8 \ A

Therefore, the bottom current is 12.8 A to the right.

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