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NeTakaya
3 years ago
9

Find the quotient 4/5,389

Mathematics
2 answers:
timurjin [86]3 years ago
7 0

Answer:

0.000742253 or .07%

Step-by-step explanation:

Olegator [25]3 years ago
5 0

Answer:

7.42 x 10^-4

0.000742

Step-by-step explanation:

0.

5389 | 4

0.0

5389 | 40

0.00

5389 | 400

0.000

5489 | 4000

0.0007

5489 | 40000

5489 | 2277

0.00074

5489 | 22770

5489 | 814

0.00074 so on

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PLEASE HELP NOW!<br> (-2, -4) and (-3, -3) in a linear equation
chubhunter [2.5K]

The linear equation is y = -x - 6

Step-by-step explanation:

To form a linear equation from two points lie on the line which the equation represented it

  • Find the slope of the line by using the formula m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}
  • Then use the slope-intercept form of the equation y = m x + b
  • To find the value of b substitute x and y of the equation by the coordinates of one of the two given points

∵  Points (-2 , -4) and (-3 , -3) lie on the line

∴ x_{1} = -2 and x_{2} = -3

∴ y_{1} = -4 and y_{2} = -3

- Substitute these values in the formula of the slope

∵ m=\frac{-3-(-4)}{-3-(-2)}=\frac{-3+4}{-3+2}=\frac{1}{-1}

∴ m = -1

∵ The form of the equation is y = m x + b

∵ m = -1

∴ y = (-1) x + b

∴ y = -x + b

To find b substitute x and y in the equation by the coordinates of

point (-2 , -4) OR (-3 , -3)

∵ x = -3 and y = -3

∴ -3 = -(-3) + b

∴ -3 = 3 + b

- Subtract 3 from both sides

∴ -6 = b

∴ The equation is y = -x + (-6)

∴ y = -x - 6

The linear equation is y = -x - 6

Learn more:

You can learn more about linear equation in brainly.com/question/4326955

#LearnwithBrainly

4 0
4 years ago
How do i solve v=pi/3*r (squared)h for h
Colt1911 [192]
V=\dfrac{\pi}{3}\cdot r^2h\ \ \ \ \ |multiply\ both\ sides\ by\ 3\\\\\pi r^2h=3V\ \ \ \ |\divide\ both\ sides\ by\ \pi r^2\\\\\boxed{h=\dfrac{3V}{\pi r^2}}
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3 years ago
Find the coordinates of the midpoint of VW with endpoint V(-2,-6) and W(x+2,y+3)
mariarad [96]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ V(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-6})\qquad W(\stackrel{x_2}{x+2}~,~\stackrel{y_2}{y+3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{(x+2)-2}{2}~~,~~\cfrac{(y+3)-6}{2} \right)\implies \left( \cfrac{x}{2}~~,~~\cfrac{y-3}{2} \right)

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3 years ago
(4x+3)(2x-5)<br><br> Help please 10 points
Yanka [14]

Answer:

Step-by-step explanation:

hello :

(4x+3)(2x-5)=0

4x+3=0 or 2x-5=0

x= -3/4 or x=5/2

5 0
4 years ago
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Nick starts with 20 milligrams of a radioactive substance. The amount of the substance decreases by 14 each week for a number of
zlopas [31]

Answer:

Eric's expression is :

20(\frac{1}{4})^w

and Andrea's is :

(1-0.5)^w

In Eric's expression, 20 represents the initial amount of substance with which he has started the experiment. \thinspace \frac{1}{4}\thinspace is the amount of substance left after each time period (in this case, each week).The variable w in this case represents the number of weeks.

Andrea's expression can be written as :

1\cdot (1-0.5)^w

The one outside of parentheses represents the initial amount of the substance. The one inside of parentheses represents 100% of the original amount of the substance. 0.5 represents the 50% of the substance that is lost each time period. The variable w in this case represents the number of weeks.

8 0
3 years ago
Read 2 more answers
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