Table A represent a function, and Table B does not.
Why?
Table to be a function, need to satisfy following conditions (look at the .jpeg image attached with this answer):
1. condition: In first circle, EVERY element has to be connected with SOME of the elements in second circle
2. condition: In first circle, there MUSTN'T be an element that has MORE THAN ONE connection with elements in second circle
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Table A satisfies BOTH of these conditions; that is why table A is indeed a function.
Table B satisfies FIRST condition but it does not satisfy the SECOND condition, that is why it is NOT a function.
The answer is parallelograms :-)
12x - 56 = y. Hope it helps! :) If you could vote my answer as the brainiest, that would be awesome! :)
Answer:
B
Step-by-step explanation:
1.(5x^3)(xy^4 -2x^3y)
2.5x^4y^4 -10x^6y
<h2>(x, y) = (x, 2 + 5/6 x)</h2>
Step-by-step explanation:
-5x + 6y = 12
y = 5/6x + 2
<h2>_______________</h2>
-5x + 6y = 12
-5x + 6(5/6x + 2) = 12
-5x + 5x + 12 = 12
x real numbers
(x, y) = (x, 2 + 5/6 x)