Answer:
66.24 (This answer does not match to any of the options...)
Step-by-step explanation:
This shape can be divided into 2 different shapes. A triangle and a rectangle.
Area of a Triangle =
× base × height
=
× 8.8 × 7.8
= 34.32
Area of a Rectangle = Length × Width
= (19.2 - 7.8) × (8.8 - (3+3))
= 11.4 × 2.8
= 31.92
Total area = 34.32 + 31.92 = 66.24
Answer: y=66
I hope it helps you!
Answer: 19.20
Step-by-step explanation: What I did was figure out what 10% of 12 was (1.2) then multiplied it by 6 which was 7.2. Then I added that to 12 and got 19.2.
Let me know if this was helpful! :D
Answer:
![\boxed{\textsf{\pink{ Hence the TSA of the cuboid is $\sf 32x^2$}}}.](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctextsf%7B%5Cpink%7B%20Hence%20the%20TSA%20of%20the%20cuboid%20is%20%24%5Csf%2032x%5E2%24%7D%7D%7D.)
Step-by-step explanation:
A 3D figure is given to us and we need to find the Total Surface area of the 3D figure . So ,
From the cuboid we can see that there are 5 squares in one row on the front face . And there are two rows. So the number of squares on the front face will be 5*2 = 10 .
We know the area of square as ,
Hence the area of 10 squares will be 10x² , where x is the side length of each square. Similarly there are 10 squares at the back . Hence their area will be 10x² .
Also there are in total 12 squares sideways 6 on each sides . So their surface area will be 12x² . Hence the total surface area in terms of side of square will be ,
Now let's find out the TSA in terms of side . So here the lenght of the cuboid is equal to the sum of one of the sides of 5 squares .
![\sf\implies 5x = l \\\\\sf\implies x = \dfrac{l}{5} \\\\\qquad\qquad\underline\red{ \sf Similarly \ breadth }\\\\\sf\implies b = 3x \\\\\sf\implies x = \dfrac{ b}{3}](https://tex.z-dn.net/?f=%5Csf%5Cimplies%205x%20%3D%20l%20%5C%5C%5C%5C%5Csf%5Cimplies%20x%20%3D%20%5Cdfrac%7Bl%7D%7B5%7D%20%5C%5C%5C%5C%5Cqquad%5Cqquad%5Cunderline%5Cred%7B%20%5Csf%20Similarly%20%5C%20breadth%20%7D%5C%5C%5C%5C%5Csf%5Cimplies%20b%20%3D%203x%20%20%5C%5C%5C%5C%5Csf%5Cimplies%20x%20%3D%20%5Cdfrac%7B%20b%7D%7B3%7D)
![\rule{200}2](https://tex.z-dn.net/?f=%5Crule%7B200%7D2)
Hence the TSA of cuboid in terms of lenght and breadth is :-
![\sf\implies TSA_{(cuboid)}= 10x^2+10x^2+12x^2\\\\\sf\implies TSA_{(cuboid)}= 20\bigg(\dfrac{l}{5}\bigg)^2+12\bigg(\dfrac{b}{3}\bigg) \\\\\sf\implies TSA_{(cuboid)}= 20\times\dfrac{l^2}{25}+12\times \dfrac{b^2}{9}\\\\\sf\implies \boxed{\red{\sf TSA_{(cuboid)}= \dfrac{4}{5}l^2 +\dfrac{4}{3}b^2 }}](https://tex.z-dn.net/?f=%5Csf%5Cimplies%20TSA_%7B%28cuboid%29%7D%3D%2010x%5E2%2B10x%5E2%2B12x%5E2%5C%5C%5C%5C%5Csf%5Cimplies%20TSA_%7B%28cuboid%29%7D%3D%2020%5Cbigg%28%5Cdfrac%7Bl%7D%7B5%7D%5Cbigg%29%5E2%2B12%5Cbigg%28%5Cdfrac%7Bb%7D%7B3%7D%5Cbigg%29%20%5C%5C%5C%5C%5Csf%5Cimplies%20TSA_%7B%28cuboid%29%7D%3D%2020%5Ctimes%5Cdfrac%7Bl%5E2%7D%7B25%7D%2B12%5Ctimes%20%5Cdfrac%7Bb%5E2%7D%7B9%7D%5C%5C%5C%5C%5Csf%5Cimplies%20%5Cboxed%7B%5Cred%7B%5Csf%20TSA_%7B%28cuboid%29%7D%3D%20%5Cdfrac%7B4%7D%7B5%7Dl%5E2%20%2B%5Cdfrac%7B4%7D%7B3%7Db%5E2%20%7D%7D)
I am almost positive that the answer could be 8 feet below sea level