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2 years ago

Q3. A bag contains 7 red balls and 3 green balls. A ball is taken out replaced.

Mathematics

1 answer:

ycow [4]2 years ago

7 0

Part (a)

There are 7 red out of 7+3 = 10 total

<h3>Answer: 7/10</h3>

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Part (b)

We have 3 green out of 10 total

<h3>Answer: 3/10</h3>

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Part (c)

3/10 is the probability of getting green on any selection. This is because we put the first selection back (or it is replaced with an identical copy)

So (3/10)*(3/10) = 9/100 is the probability of getting two green in a row.

<h3>Answer: 9/100</h3>

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Part (d)

Similar to part (c) we have 7/10 as the probability of getting red on each independent selection.

(7/10)*(7/10) = 49/100

<h3>Answer: 49/100</h3>

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Part (e)

7/10 is the probability of getting red and 3/10 is the probability of getting green. Each selection is independent of any others.

(7/10)*(3/10) = 21/100

<h3>Answer: 21/100</h3>

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Part (f)

We have the exact same set up as part (e). Notice how (7/10)*(3/10) is the same as (3/10)*(7/10).

<h3>Answer: 21/100</h3>

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Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

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where

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t is the time (in seconds)

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When the objects hit the ground, h = 0

then;

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For a quadratic equation: ax^2+bx+c=0 ......[1]

the solution for the equation is given by:

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

On comparing the given equation with [1] we have;

a = -16 ,b = 80 and c = 300

then;

$t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}$

$t= \frac{-80\pm \sqrt{6400+19200}}{-32}$

$t= \frac{-80\pm \sqrt{25600}}{-32}$

Simplify:

$t = -\frac{5}{2}$ = -2.5 sec and $t = \frac{15}{2}$ = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

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