Answer:
Step-by-step explanation:5,7 3,9
Since width is the smaller value, set width=x. That wold mean that length=x+3. Since Area=width*length, 40=x(3+x). Distribute the x to give you 40=3x+x^2. Set the equation equal to 0 giving you x^2+3x-40=0. Factor the equation to give you (x+8)(x-5)=0. Set each factor equal to 0. x+8=0 gives you x=-8 & x=-5 gives you x=5. Since we're working with lengths of objects, it can't be negative. Therefore, your width is 5. To find length, substitute width into the original expression (x+3). Therefore, length is 5+3=8.
The net change between the given values of the variable is 6a - 6
<h3>How to determine the net change between the given values of the variable?</h3>
The given parameters are
g(x) = 6x
Where
x = 1 and x =a
Calculate g(1) and g(a)
So, we have
g(1) = 6 * 1
g(1) = 6
g(a) = 6 * a
g(a) = 6a
The net change between the given values of the variable is
Change = g(a) - g(1)
So, we have
Change = 6a - 6
Hence, the net change between the given values of the variable is 6a - 6
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Ur answer is. 5 y^2+4y+14 because I went through it in class