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Flauer [41]
2 years ago
10

A hiker travels 1.13 kilometers south, then travels 2.25 kilometers east. What’s the hiker’s displacement for the trip?

Mathematics
1 answer:
lara31 [8.8K]2 years ago
5 0

Answer:

Total displacement = 2.52 kilometers [south east]a^2 + b^2 = c^2\\1.13^2 + 2.25^2 = c^2\\c^2 = 6.3394\\c = 2.52

Step-by-step explanation:

By the Pythagorean Theorem:

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In a sentence.
Allisa [31]

Answer:

Kelsey can buy 9 books.

Step-by-step explanation:

If Kelsey wants to buy as much books as possible with 30$, multiply 3$ by 9 (books) which is 27$.

30$-27$ is 3$ so she will have 3$ extra dollars to use for shipping.        2$ is the price for shipping so she will have an extra dollar.

<em>I hope this was helpful! :) (Please rate/heart this if helpful)</em>

8 0
1 year ago
Please help me ! i'm bad @ math (::
Elodia [21]
The correct answer is 34

To solve first multiply whole number
2 times 16 = 32
Then you multiply the numerator in the fraction
1 times 16 =16  
The answer is know 32 and 16/8 
The last step is simplifying. 8 goes into 16 two times
So the final procedure is 32+2= 34


3 0
3 years ago
Read 2 more answers
Your summer job will pay you $75 for the first week. Your boss will give you a bonus of $25 per week.
ANEK [815]

Answer:

a.

1st week= $75

2nd week= $100

3rd week= $125

4th week= $150

b.

8th week= $250

c.

(If your summer is 13 weeks long)

$2925

Step-by-step explanation:

Hope this helps!

8 0
3 years ago
I really need help with this one, It is order of operations.
Ksju [112]

Answer:

I'm gonna go Step d

Step-by-step explanation:

because the 1+7x Addition doesn't really make sense me you can't add 1 to 7x they are not like terms

4 0
3 years ago
Mr .Baker has baked some muffins. If he packs them in boxes of 4, he will have 3 left over. If he packs them in boxes of 5, he w
babunello [35]

Answer:

\boxed{43}

Step-by-step explanation:

I think the easiest way to solve this problem is by brute force: trial and error.

We must find numbers that when divided by  

  • 4 leave 3 (4n + 3)
  • 5 leave 3 (5n + 3)
  • 6 leave 1  (6n + 1)

Here is a list of multiples of the integer n that satisfy the three conditions. \begin{array}{c|ccc}\mathbf{n} & \mathbf{4n+ 3} & \mathbf{5n + 3} & \mathbf{6n + 1}\\1 & 7 & 8 & 7\\2 & 11 & 13 & 13\\3 & 15 & 18 & 19\\4 & 19 & 23 & 25\\5 & 23 & 28 & 31\\6 & 27 & 33 & 37\\7 & 31 & 38 & \mathbf{43}\\8 & 35 & \mathbf{43} & 49\\9 & 39 & 48 & 55\\10 & \mathbf{43} & 53 & 61\\\end{array}\\\text{The only number that is common to all three lists is $\mathbf{43}$.}\\\text{The smallest possible number of muffins Mr. Baker could have baked is $\boxed{\mathbf{43}}$.}

Check:

43 \div 4 = 10R3\\43 \div5 = 8R3\\43 \div 6 = 7R1

OK .

6 0
3 years ago
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