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tangare [24]
2 years ago
10

If ON = 7x - 5, LM = 6x + 4, NM = x + 6, and OL = 8y + 3, find the values of X and Y for which LMNO must be a parallelogram. Ple

ase show your work.
L is top left, M is top right, O is bottom left, N is bottom right.
Mathematics
1 answer:
Sladkaya [172]2 years ago
6 0

The values of x and y that will make LMNO a parallelogram are: x = 9, y = 1.5.

<h3>Properties of a Parallelogram</h3>
  • The opposite sides of a parallelogram are parallel to each other and are also of equal lengths.
  • Diagonals of a parallelogram are congruent to each other and also bisect each other into equal halves.

Therefore:

ON = LM

Substitute

7x - 5 = 6x + 4

Add like terms

7x - 6x = 5 + 4

x = 9

OL = NM

Substitute

8y + 3 = x + 6

Plug in the value of x

8y + 3 = 9 + 6

8y + 3 = 15

8y = 15 - 3

8y = 12

y = 12/8

y = 1.5

Therefore, the values of x and y that will make LMNO a parallelogram are: x = 9, y = 1.5.

Learn more about parallelogram on:

brainly.com/question/7200842

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3 years ago
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Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
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