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3 years ago

Find the similarity ratio of a cube with volume 216 ft to a cube with volume 1000ft

1 answer:

3 0

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-----------------------------\\\\
\cfrac{s^3}{s^3}\implies \cfrac{216}{1000}\implies \cfrac{\sqrt[3]{216}}{\sqrt[3]{1000}}\implies \cfrac{s}{s}\impliedby \textit{similarity ratio}$

and simplify it away

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Step-by-step explanation:

We need to simplify the expression: $2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$

First we will solve terms inside the bracket

$2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$

Converting mixed fraction $1\frac{1}{2} y$ into improper fraction, we get: $\frac{3}{2}y$

Replacing the term:

$2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-\frac{3}{2}y +3)$

Now, taking LCM of: 5,3,4,2 we get 60

Now multiply 60 with each term inside the bracket

$2(\frac{3}{5}x\times60+\frac{2}{3}y\times60-\frac{1}{4}x\times60-\frac{3}{2}y\times60 +3\times60)\\2(3x\times12+2y\times20-1x\times15-3x\times30-3\times60)\\2(36x+40y-15x-90y-180)$

Now, combine like terms

$2(36x-15x-90y+40y-180)\\2(21x-50y-180)$

Now, multiply all terms with 2

$42x-100y-360$

So, Simplifying the expression: $2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$ we get $\mathbf{42x-100y-360}$

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