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Olin [163]
3 years ago
11

Find the similarity ratio of a cube with volume 216 ft to a cube with volume 1000ft

Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-----------------------------\\\\
\cfrac{s^3}{s^3}\implies \cfrac{216}{1000}\implies \cfrac{\sqrt[3]{216}}{\sqrt[3]{1000}}\implies \cfrac{s}{s}\impliedby \textit{similarity ratio}

and simplify it away
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Ordinal level

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Thus, variable is measured at ordinal level.

8 0
3 years ago
I need help on #17 can someone please help me?
sashaice [31]

Answer:

t=2

Step-by-step explanation:

We are given the equation

h = -16t²+36t+1

Next, we are asked to find how long the ball was in the air (the time, in seconds) if Casey caught the ball 9 feet above the ground (9 feet is the height).

Therefore, as 9 is the height, we can plug that into our equation to get

9 = -16t²+36t+1

To make this a quadratic equation that is easy to factor, we can subtract 9 from both sides to get

-16t²+36t-8=0

To factor this, we need to find two values that add up to 36 and multiply to (-16)*(-8) = 128. With a little guess and check, I found the numbers 32 and 4 to work well. We can then make the equation

-16t²+32t+4t-8=0

-16t(t-2) + 4(t-2) = 0

(-16t+4)(t-2) = 0

Therefore, to solve for the equation being 0, or 9 = -16t²+36t+1, either (t-2) or (-16t+4) must equal 0

t-2 = 0

t=2

-16t+4 = 0

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t = 1/4

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3 0
3 years ago
What needs to be corrected in this construction of a line parallel to [\overleftrightarrow?]AB passing through C?
JulsSmile [24]

The option that needs to be corrected in this making of a that is line parallel to AB via C is known to be the second arc should be centered at C.

<h3>Why should the second arc be centered at C.</h3>

The second arc should be centered at C because as it crosses via Line C, it is seen that it was not touching or intersecting AB and so one can say that it is a  parallel to it.

Looking at the other lines, you will see that they are all touching AB and are not running parallel to it.

Therefore, The option that needs to be corrected in this making of a that is line parallel to AB via C is known to be the second arc should be centered at C.

See full question below

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B) The first arc should pass centered at C.

C) The second arc should be centered at C.

D) The second arc should cross the first arc.

E) The second arc should be centered at F

Learn more about  line parallel from

brainly.com/question/1439525

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7 0
1 year ago
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-40 + 10a = -70

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10a = -30

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A = -3

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3 years ago
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