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2 years ago

Which of the x-values are solutions to the following inequality? X < 365

Mathematics

1 answer:

e-lub [12.9K]2 years ago

4 0

A and b because both values are less than 365

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Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$

It has critical points where the first order derivatives vanish:

$L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}$

$L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y$

$L_\lambda=x^2+y^2-4=0$

From the first two equations we get

$-\dfrac1{2x}=-\dfrac4y\implies y=8x$

Then

$x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}$

At these critical points, we have

$f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125$ (maximum)

$f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125$ (minimum)

5 0

3 years ago

What is the probablility that a student plays on a sports team given they play an instrument.

cestrela7 [59]

Answer:

These two things have litterally nothing to do with eachother

Step-by-step explanation:

50% chance i guess?

8 0

2 years ago

Read 2 more answers

If you launch the cannonball from the ground instead (hi=0), what does that change in the original equation?

ikadub [295]

Answer:

the value of hi changes from 58 to 0:

h(t) = -4.9t^2 +19.8t

Step-by-step explanation:

If the initial height changes, then the term in the equation that represents that height will change. The initial height term is hi, so it changes from 58 to 0.

$h(t)=-4.9t^2+19.8t+0\\\\\boxed{h(t)=-4.9t^2+19.8t}$

7 0

3 years ago

Triangle PQR has coordinates P(–8, 3), Q(–8, 6), and R(–3, 6). If the triangle is translated by using the rule (x, y) right-arro

omeli [17]

Answer:

Step-by-step explanation:

The rule (x, y ) → (x + 4, y - 6 )

means add 4 to the original x- coordinate and subtract 6 from the original y- coordinate, thus

P(- 8, 3 ) → P'(- 8 + 4, 3 - 6 ) → P'(- 4, - 3 )

Q(- 8, 6 ) → Q'(- 8 + 4, 6 - 6 ) → Q'(- 4, 0 )

R(- 3, 6 ) → R'(- 3 + 4, 6 - 6 ) → R'(1, 0 )

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3 years ago

How many labeled points are between points B and U? four zero two seven

blondinia [14]

Your answer is four love!

5 0

3 years ago