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frosja888 [35]
3 years ago
11

The perimeter of a rectangle is 60. The length is twice the width. Find the length and width.

Mathematics
1 answer:
prohojiy [21]3 years ago
8 0

Step-by-step explanation: Our first task in this problem is to setup variables representing <em>length</em> and <em>width</em> and we do that by using the second sentence.

<em><u>The length is twice the width</u></em>

So if we call our width <em>x</em>, that means that our length is 2 times <em>x</em> or 2x

Width of the rectangle ⇒ <em>x</em>

Length of the rectangle ⇒ <em>2x</em>

Before moving on, go ahead and draw a picture of your

rectangle so that you can visualize what's going on.

I have done this for you below.

We label our widths <em>x</em> and our lengths <em>2x</em>.

Now we can use the first sentence to setup our equation.

The perimeter of a rectangle is the distance

around the outside of the figure.

So if our perimeter is 60, that means that x + x + 2x + 2x = 60.

Simplifying by combining like terms, we get 6x = 60.

Now dividing both sides by 6, we find that <em>x = 10</em>.

Since <em>x</em> represents width, our width is 10.

Our length therefore with be <em>2(10)</em> or 20.

So our width is 10 and our length is 20.

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