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frosja888 [35]
3 years ago
11

The perimeter of a rectangle is 60. The length is twice the width. Find the length and width.

Mathematics
1 answer:
prohojiy [21]3 years ago
8 0

Step-by-step explanation: Our first task in this problem is to setup variables representing <em>length</em> and <em>width</em> and we do that by using the second sentence.

<em><u>The length is twice the width</u></em>

So if we call our width <em>x</em>, that means that our length is 2 times <em>x</em> or 2x

Width of the rectangle ⇒ <em>x</em>

Length of the rectangle ⇒ <em>2x</em>

Before moving on, go ahead and draw a picture of your

rectangle so that you can visualize what's going on.

I have done this for you below.

We label our widths <em>x</em> and our lengths <em>2x</em>.

Now we can use the first sentence to setup our equation.

The perimeter of a rectangle is the distance

around the outside of the figure.

So if our perimeter is 60, that means that x + x + 2x + 2x = 60.

Simplifying by combining like terms, we get 6x = 60.

Now dividing both sides by 6, we find that <em>x = 10</em>.

Since <em>x</em> represents width, our width is 10.

Our length therefore with be <em>2(10)</em> or 20.

So our width is 10 and our length is 20.

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kirill [66]
(-1, 6) is your answer
6 0
3 years ago
In the circle below, suppose m FEH=272º and m EFG=116º. Find the following.​
adoni [48]

Answer:

m∠FEH = 44°

m∠EHG =  64°

Step-by-step explanation:

1) The given information are;

The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°

Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°

Therefore, angle subtended by arc ∠HGF at the center = 88°

The angle subtended by arc ∠HGF at the circumference = m∠FEH

∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)

m∠FEH = 44°

2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°

The sum of angles in a quadrilateral = 360°

Therefore;

m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)

m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°

m∠EHG =  64°.

5 0
3 years ago
George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4
antiseptic1488 [7]

Hello,

Question:

George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging?

We know:

He jogged 9 1/2 miles during October and November

1/4 mile every day

Answer:

9 and 1 over 2 divided by 1 over 4


6 0
3 years ago
Read 2 more answers
The following data points represent the number of jars of honey Martha the Bear consumed each day this week. \qquad4,4,5,2,2,3,
ikadub [295]

What are the commas for?  I think this was copied wrong, but I'd say use the # of bears eaten/jars as the (y) variable and the # of days as the (x) variable.

3 0
4 years ago
I need help plz and plz explain why plz
Mariana [72]

Answer:

156 minutes

Step-by-step explanation:

2 hrs=120 minutes

3/5 hr=3/5 *60=36 minutes

120+36=156 minutes

hope this helps

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6 0
3 years ago
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