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3 years ago

13

What is the perimeter

2 answers:

AleksAgata [21]3 years ago

5 0

Answer:

25.05 in.

Step-by-step explanation:

hope this helps

Sloan [31]3 years ago

4 0

25.05 in

Perimeter you just add all of the sides together.

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What focal-length eyepiece is needed if your eye can resolve objects 0.10 mm apart at a distance of 25 cm?

Kay [80]

M=d/f so, f=d/M f=25/.01. =2500cm

7 0

3 years ago

Find the value of b.

Nesterboy [21]

Answer: $230^{\circ$

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume $\overline{AB}$ and $\overline{BC}$ are tangents to the circle.

$\overline{BO} \cong \overline{BO}$ (reflexive property)
$\overline{AB} \cong \overline{BC}$ (tangents drawn from a common external point are congruent)
$\angle BAO \cong \angle BCO$ (right angles are congruent)

Therefore, we know $\triangle ABO \cong \triangle CBO$ by HL.

Thus, by CPCTC,

$\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}$

This means the measure of minor arc AC is $130^{\circ}$ , and thus $b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}$

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2 years ago

A company charges $25 a day for a car rental along with a $60 one time fee. Complete the table to determine the cost to rest the

saw5 [17]

Answer:

Step-by-step explanation:

cost

d1 85

d2 110

d3 135

d4 160

3 0

3 years ago

Simplify b^2/3a^-4 what's the answer

Andru [333]

Combine like terms. Is there a picture for this?

6 0

3 years ago

Read 2 more answers

consider the function f(x) = x2 2x – 15. what are the x-intercepts of the function? left-most x-intercept: ( , 0) right-most x-i

eimsori [14]

we have

$f(x)=x^{2} +2x-15$

we know that

The x-intercept is the value of x when the value of the function is equal to zero

so

in this problem

Find the roots of the function

equate the function to zero

$x^{2} +2x-15=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2} +2x=15$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} +2x+1=15+1$

$x^{2} +2x+1=16$

Rewrite as perfect squares

$(x+1)^{2}=16$

Square root both sides

$(x+1)=(+/-)\sqrt{16}$

$(x+1)=(+/-)4$

$x=-1(+/-)4$

$x1=-1+4=3$

$x2=-1-4=-5$

$x^{2} +2x-15=(x-3)(x+5)$

therefore

<u>the answer is</u>

the x-intercepts are the points $(3,0)$ and $(-5,0)$

3 0

3 years ago

Read 2 more answers