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4 years ago

Which function represents a vertical stretch of an exponential function

1 answer:

7 0

Vertical stretch means the graph stretches upward, rising more rapidly than the original, the graph is steeper than the original.

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Using the formula z=Kx/y If z = 6 when x = 3 and y = 4, then what is z when x = 5 and y = 2?

Veseljchak [2.6K]

Answer:

z=kx/y

zy=kx

zy/x=kx/x ( divided both side by x. to find k)

k=zy/x

k=6×4/3(z=6,y=4,x=3)

k=24/3

k=8

so z=kx/y

z=8×5/2(replace the numbers in the place of variables,k=8,x=5,y=2)

z=40/2

z=20

3 0

3 years ago

Find the value of a and m∠ZWT if ZW is an

nevsk [136]

If ZW is an altitude of △XYZ, then m∠ZWY = 90°

3a + 5 + 5a + 13 = 90
8a + 18 = 90
8a = 72
a = 72/8
a = 9

m∠ZWT = 3a + 5 = 3*9 + 5 = 27 + 5 = 32°

3 0

4 years ago

The Turtle and Achilles compete. They start at the same time from the same place. Achilles runs at a speed of 13 mph while the T

grandymaker [24]

Answer:

2 minutes.

Step-by-step explanation:

Let t be the time taken in competition and the distance covered by Achilles be x miles.

We have been given that when Achilles reaches the finish line, the Turtle is 2/5 of a mile behind him. This means that distance covered by turtle will be: $x-\frac{2}{5}$ .

Achilles runs at a speed of 13 mph while the Turtle moves at a speed of 1 mph.

Since we know that $\text{Time}=\frac{\text{Distance}}{\text{Speed}}$ , so we can set two equations for time taken by Achilles and turtle as:

$t=\frac{x}{13}...(1)$

$t=\frac{(x-\frac{2}{5})}{1}...(2)$

From equation (1) we will get,

$x=13t$

Upon substituting this value in equation (2) we will get,

$t=\frac{13t-\frac{2}{5}}{1}$

Let us have a common denominator.

$t=\frac{\frac{65t-2}{5}}{1}$

$t=\frac{65t-2}{5}$

Upon multiplying both sides of our equation by 5 we will get,

$5t=5\times \frac{65t-2}{5}$

$5t=65t-2$

$5t-65t=65t-65t-2$

$-60t=-2$

$t=\frac{-2}{-60}$

$t=\frac{1}{30}$

So, the competition took 1/30 hour, let us convert our given time in minutes.

$\frac{1}{30}\text{ hour}\times \frac{60\text{ minutes}}{\text{hour}}$

$\frac{1}{30}\times 60\text{ minutes}$

$2\text{ minutes}$

Therefore, the competition took 2 minutes.

8 0

3 years ago

Can you help me solve these problems

Arturiano [62]

2) I agree with your first step: assigning a variable to Miss B's age. Let's specifically say that this is her age in the present.

In 12 years, her age will be 12 more than in the present, or $x+12$ . And this is the same as three times her age 32 years ago. So, her age 32 years ago was 32 less than in the present, so $x-32$ , and we know it's three times this, so $3(x-32)$ .

Now, we can write an equation and solve for x

$x+12=3(x-32)\\x+12=3x-96\\12=2x-96\\108=2x\\54=x$ .

Thus, Ms. B is 54 years old now.

3) Your intuition for finding the LCD is correct; to add fractions, we need like denominators. But remember that the LCD is the least common multiple of the denominators. Using the simplest method for finding this (listing multiples), we have 4, 8, 12, 16, 20, 24, 28, ... and 6, 12, 18, 24, 30, ... and 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, .... Of these, the lowest common number is 24.

So we want to use 24 as our LCD.

$\dfrac{18x+4x+4}{24}= \dfrac{72-12x}{24}$

We can multiply both sides of the equation by 24 and then solve for x.

$18x+4x+4=72-12x\\18x+4x+12x=72-4\\34x=68\\x=2$

It's often a good idea to check your work. Plugging in 2 for x in the original equation, we see that 2 = 2.

6 0

4 years ago

I’ll do all of your math homework and get u an A.

Luden [163]

Answer:

you can use a calculator for this i think

Step-by-step explanation:

6 0

3 years ago