Answer:
Explanation:
The distance traveled by June, from A to D, is the sum of the distance from A to C plus the distance from C to D:
- Travel from A to D = Distance AC + Distance DC.
<u>1) Find the distance AC</u>
- Triangle ABC is a right triangle, from which you have to calculate the hypotenuse (AC), knowing angle A (50º), and its adjacent leg (217 m).
- AC = 217m / cos (50º) = 337.59m
<u>2) Find the distance DC</u>
First, you need to calculate the side BC which is a common side of both triangles ABC and DBC.
You can use Pythagora's or a trigonometric function (tangent or sine).
- tan (50º) = BC / 217 m ⇒ BC = 217 m × tan (50º) = 258.61 m
Now you can use Pythagora's theorem to find the distance DC, which is the hypotenuse of the triangle DBC:
- DC² = (170m)² + (258.62)² = 95,779.41m²
<u>3) Find the total distance traveled from A to D</u>
- Travel from A to D = Distance AC + Distance DC = 337.59m + 309.48m = 647.07 m ≈ 647m.
A) 2 units
B) yes
For A) |5-3|=|2|=2 is the distance from his house to school.
For B)
The distance from his house to school is 2 units; the distance from school to the grocery store is |3--9|=|12|=12. The total distance is 2+12 = 14.
The distance from his house to school is 2 units; the distance from school to the community center is |-4-6|=|-10|=10. The total distance is 2+10 = 12.
The distance from the house to the school to the grocery store is greater.
Is the equation supposed to be like this
(c o f)(5)?
Answer:
Step-by-step explanation:
hm 2x2=4
