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Sergeeva-Olga [200]
3 years ago
11

Find the quotient of 1260 ÷ 15. then, show a method to justify your answer.

Mathematics
1 answer:
Blizzard [7]3 years ago
7 0

Answer:

it is 84

Step-by-step explanation:

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Find all solutions in the interval [0, 2π). tan x + sec x = 1
svp [43]
Use the identity 
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x  = 1 + tan^2x - 2 tan x
0 = -2 tanx 

tan x = 0 

x =  0, π 
π is an extraneous root because sec 180 = -1 
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6 0
3 years ago
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maxonik [38]

Answer: A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An
Gnom [1K]
I would solve this using tangents.  Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.

Now write the tangent ratios:
tan A = \frac{h+70}{40}  , tan B = \frac{70}{40}

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
tan (A-B) = \frac{tanA - tanB}{1+tan A  tan B}
Plug in what we know:
tan(9) = \frac{ \frac{h+70}{40} -  \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}
tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}
h = \frac{650 tan(9)}{4-7 tan(9)}
h = 35.6
7 0
3 years ago
4. The figure shows a rectangular tank.
dalvyx [7]

Answer:

20 L volume and 12.5 cm depth.

Step-by-step explanation:

See attached image.

6 0
1 year ago
If it’s greater than or equal to a negative will it’s second option switch to a positive?
Oduvanchick [21]

Answer:

yes

Step-by-step explanation:

yes it will

7 0
3 years ago
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