Answer:
The proportion of the population that is homozygous for the non-wiggling allele is 0.3056.
Step-by-step explanation:
Denote the variables as follows:
<em>q²</em> = number of people who are homozygous for the scalp-wiggling allele.
<em>p²</em> = number of people who are homozygous for the non-wiggling allele.
It is provided that the proportion of the population who are homozygous for the scalp-wiggling allele is, <em>q²</em> = 0.20.
Compute the value of <em>q</em> as follows:
Compute the value of <em>p</em> as follows:
Compute the proportion of the population who are homozygous for the non-wiggling allele as follows:
Thus, the proportion of the population that is homozygous for the non-wiggling allele is 0.3056.
Here is the answer:
n+n+1+n+2
=3n+3. Hope it help!
Answer:
I would use distributive property
Step-by-step explanation:
Okay do :
(1)3x-4y = 7
(2)7x - y = 33 -
________________
multiply one of the equations to get the y terms to be the same or the x terms to be the same . In this case it's easier to make the y terms the same . to do this you have to multiply the whole of 7x - y =33 by 4 .
This gives you :
3x -4y =7
28x -4y = 132 - (when signs are the same you take away,when different you add)
______________
25x = 125 ( the -4y cancel out )
divide both sides by 25 to give you the value of x
x= 5 .
Now substitute x=5 into either equation (1) or (2)
It should give you the same answer in both equations .
(1)3x-4y = 7
so you should have :
(3x5)-4y=7
15 -4y = 7
Take away 15 from both sides to get rid of the 15 .
-4y = (7-15)
-4y = -8
divide both sides by -4 to get the value of y .
y = 2 .
to check whether your values are correct substitute y = 2 and x=5 into equation (1) or (2) .
(2) 7x -y = 33
(7x 5) -2
=35 -2
=33
(you can try both equations , it should work on both of the m)
I hope that was helpful :)
