In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
R(t) = 4t
A(r) = π(r^2)
a) A(t) = A[r(t)] = π[r(t)]^2 = π[4t]^2 = 16π(t^2)
b) t = 4,
A(4) = 16*3.14*(16)^2 = 12,861.44
4/5(v - 7) = 2...distribute the 4/5 thru the parenthesis
4/5v - 28/5 = 2 ...multiply everything by 5
4v - 28 = 10...add 28 to both sides
4v = 10 + 28
4v = 38
v = 38/4 reduces to 19/2 or 9 1/2 <==
Answer:
10 gallons
Step-by-step explanation:
She used 12 gallons this week and used 20% more than last week. That means 12 gallons is 120% of last weeks gas. Since 12 times 10 equals 120, then to find 20% you do 20 divided 10 and subtract the answer from 12.
20% is 2 because 20 divided by 10 is 2. 12 minus 2 is 10
Hope this helps :)
C the vertex of the function