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Sladkaya [172]
3 years ago
15

- (64 - 36 + 5) + (45 - 87) = ?

Mathematics
1 answer:
adoni [48]3 years ago
8 0

Answer:

its -75

Step-by-step explanation:

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I need help with 14 and 16​
ArbitrLikvidat [17]

Answer:

14. (0,1)

Step-by-step explanation:

To find the solution set, substitute and evaluate each point into the given equation. If it makes it true then it is part of the solution set.

14. y = 4x + 1

(2,-1)

-1 = 4*2 + 1

-1 = 9 FALSE

(1,5)

5 = 4*-1 + 1

5 = -3 FALSE

(9,2)

2 = 4*9+1

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(0,1)

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1=1 TRUE

5 0
4 years ago
Need help with this easy math problem
NeX [460]

Answer: C h is the largest

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Please help me aspa <br><br><br><br><br><br>​
goblinko [34]

Answer:

i's 20 because it seems that it is the most successful

6 0
2 years ago
What is the domain of F(x)=9-x??<br> F F(x) &gt;9<br> G All real numbers<br> H-3 1 x59
Julli [10]
I’m pretty sure it’s h because the lines meet in the x axis
8 0
3 years ago
The number of peanuts in a 16-ounce can of Nut Munchies is normally distributed with a mean of 96.3 and a standard deviation of
andriy [413]
To calculate for the z-score we use the formula:
z=(x-μ)/σ
thus the answers to questions will be as follows:

a]<span>Carmen purchased a 16-ounce can of Nut Munchies and counted 100 peanuts. What is the z-score for this can of peanuts?
</span>x=100
μ=96.3
σ=2.4
z=(100-96.3)/2.4
z=1.542

b]<span>Angelo purchased a 20-ounce can of Gone Nuts and counted 116 peanuts. What is the z-score for this can of peanuts?
x=116
</span>μ=112.6
σ=2.8
<span>thus
z=(116-112.6)/2.8
z=1.214

c]</span><span>Carmen declares that purchasing her can of Nut Munchies with 100 peanuts is less likely than Angelo purchasing a can of Gone Nuts with 116 peanuts. Is Carmen’s statement correct? Use the definition of a z-score to support or refute Carmen’s claim.
This is very correct because because by definition of z-score, Munchies with 100 peanuts is 1.542 away from the mean as compared to Munchies with 116 peanuts which is 1.214 standard deviations from the mean hence the higher likelihood. </span>
6 0
3 years ago
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