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Novosadov [1.4K]
3 years ago
12

Which statement is incorrect?

Mathematics
1 answer:
jeka943 years ago
3 0
The interquartile range is affected by the existence of an outliner
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Ryan deposited $6,700 into an account at the Town Bank, earning 3.4% interest compounded annually. He made no deposits or withdr
Nonamiya [84]

Answer: The amount of money in his account after 4 years = $7,658.73

Step-by-step explanation:

If interest is compounded annually, then formula to compute amount :

A=P(1+r)^n, where P+ principal value, r= rate of interest, n= time ( in years).

As per given,

P= $6700 ,  r = 3.4% =0.034, n =4

A=6700(1+0.034)^4\\\\=6700(1.034)^4\\\\=6700(1.14309455234)\approx7658.73

Hence, the amount of money in his account after 4 years = $7,658.73

6 0
3 years ago
Simplify:<br> 2 11/12 + 5 1/2 + 3 3/8<br> Write you answer as a mixed number.
zysi [14]

Answer:

2\frac{11}{12} +5 \frac{1}{2} + 3\frac{3}{8} (write them out and convert them all into mixed fractions)

\frac{35}{12} + \frac{11}{2} + \frac{27}{8} (find the LCD aka least common denominator)

\frac{70}{24} + \frac{132}{24}  + \frac{81}{24} (add all numerators together)

\frac{283}{24}  (this is improper, so you need to convert back to mixed by dividing)

11\frac{19}{24} (this is your answer)

3 0
3 years ago
Write an equation in standard form of a quadratic function that has x-intercepts -2 and 5 and k=-4
bulgar [2K]

Answer:

-2x + 5 = -4k

Step-by-step explanation:

8 0
3 years ago
Please answer this question fast in two muintues
djyliett [7]

Answer:

W

Step-by-step explanation:

W is the vertex, you can see the letter above the angle

4 0
3 years ago
Read 2 more answers
What are the zeros of the function f(x)=x^2-2x-15?
valkas [14]
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
Read 2 more answers
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