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agasfer [191]
3 years ago
15

Hey if you're willing to help me with this, it will be very much appreciated, thanks maties and mates.

Mathematics
1 answer:
Nastasia [14]3 years ago
4 0

Answer:

Width=37in

Length=55in

Step-by-step explanation:

Let x in be the width dimension, the length dimension will be x+18 in. Area of a rectangle is calculated as A=lw. Given  the area as2143 sq in, x can be calculated as:

Area= x(18+x)\\\\=18x+x^2\\\\

#Substitute for every x in our function to find the true value of x:

x=37\\\\A=x^2+18x\\\\=37^2+18\times37\\\\=2035 \ in^2#l=37+18=55in

for x=38:

x=38\\\\A=x^2+18x\\\\=38^2+18\times38\\\\=2128 \ in^2#l=38+18=56in

For x=39:

x=39\\\\A=x^2+18x\\\\=39^2+18\times39\\\\=2223 \ in^2#l=39+1854in

From the calculations above, A television with a width of 37 in and length 55in has its area closest to 2143 sq in.

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