Check the picture below. You can pretty much just count the units off the grid.
Hey if you're willing to help me with this, it will be very much appreciated, thanks maties and mates.
1 answer:
Answer:
Width=37in
Length=55in
Step-by-step explanation:
Let x in be the width dimension, the length dimension will be x+18 in. Area of a rectangle is calculated as A=lw. Given the area as2143 sq in, x can be calculated as:
#Substitute for every x in our function to find the true value of x:
#l=37+18=55in
for x=38:
#l=38+18=56in
For x=39:
#l=39+1854in
From the calculations above, A television with a width of 37 in and length 55in has its area closest to 2143 sq in.
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First, you plot the coordinates to visualize the problem clearly. As you can see in the picture, the longest sides could either be one of those marked in red. This could be initially determined when you use visual estimation. We measure this using the distance formula: d = √[(x2-x1)^2 + (y2-y1)^2)]
Between coordinates (0,3) and (3,6)
d = √[(3-0)^2 + (6-3)^2)]
d= 4.24 units
Between coordinates (2,1) and (5,4)
d = √[(5-2)^2 + (4-1)^2)]
d= 4.24 units
They are of equal length. Both are the longest sides which measures 4.24 units.
Between coordinates (0,3) and (3,6)
d = √[(3-0)^2 + (6-3)^2)]
d= 4.24 units
Between coordinates (2,1) and (5,4)
d = √[(5-2)^2 + (4-1)^2)]
d= 4.24 units
They are of equal length. Both are the longest sides which measures 4.24 units.