What would happen if our bodies could not metabolize glucose?.

1 answer:

4 0

Answer: When insulin is not working as it should, blood sugar can build up, eventually spilling over into your urine. This can lead to diabetes symptoms such as increased urination and unexplained weight loss, since your body isn't able to use the energy from the foods you eat.

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Assume that when adults with smartphones are randomly selected, 57% use them in meetings or classes. If 10 adult smartphone user

blsea [12.9K]

The probability that at least 5 of them use their smartphones in meetings or classes will be 0.34.

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

The number of combinations of 5 out of 10:

$^{10}C_4=\dfrac{10!}{5!(10-5)!}=\dfrac{10!}{5!\times 5!}\\\\\\^{10}C_4=\dfrac{10\times 9\times 8\times 7\times 6}{5\times 4\times 3\times 2}\\\\\\^{10}C_4=252$

The Success factor is:

57% = 0.57

The failure factor is:

(100 - 57)%= 43%= 0.43

So the Probability will be :

0.57⁵ x 0.43⁵ x 252 ≈ 0.34

To know more about probability follow

brainly.com/question/24756209

#SPJ1

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2 years ago

If (x2 – 4) ÷ (x 2) = x – 2, which polynomial should fill in the blank below? (x 2) ´ ______ = x2 – 4 x2 – 4 x – 2 x 2 x2 – 2

bezimeni [28]

Answer:

x - 2

Explanation:

(x + 2) __x – 2__ = x2 - 4

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2 years ago

High choice best summarize Kennedy’s perspective on scientific progress

wariber [46]

Is this a true or false queston

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2 years ago

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The positive solution to the equation x^2- 4 = 6

VARVARA [1.3K]

Answer:

In the form of $a+\sqrt{b}$ ,

a = 3
b = 13

Explanation:

The equation can be rewritten as:

$x^{2} -6x-4=0$

Find the solutions using the quadratic formula:

a = 1
b = -6
c = -4

$x=\frac{-b+-\sqrt{b^{2}-4ac} }{2a} \\\\=\frac{-(-6)+-\sqrt{(-6)^{2} -4(1)(-4)} }{2(1)} \\\\=\frac{6+-\sqrt{36+16} }{2} \\\\=\frac{6+-\sqrt{52} }{2} \\\\=\frac{2(3)+-2\sqrt{13} }{2} \\\\=\left \{ {{x_{1}=3+\sqrt{13} } \atop {x_{2}=3-\sqrt{13} }} \right.$