Question

The area of a parallelogram is 8√90 and the base is 2√5. what is the height of the parallelogram?

Answer 1

Formula for the area of a parallelogram is

$A=\text{height}\cdot \text{base}.$

If $A=8\sqrt{90}\ un.^2$ and $\text{base}=2\sqrt{5}\ un.,$ then

$8\sqrt{90}=\text{height}\cdot 2\sqrt{5},\\ \\\text{height}=\dfrac{8\sqrt{90}}{2\sqrt{5}}=4\sqrt{\dfrac{90}{5}}=4\sqrt{18}=4\cdot 3\sqrt{2}=12\sqrt{2}\ un.$

Answer: the height has a length $12\sqrt{2}\ un.$