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Brut [27]
2 years ago
11

Determine the prime number between 150 and 200​

Mathematics
1 answer:
Arada [10]2 years ago
6 0

Answer:

Thus out of 16 numbers which are multiples of 6 increased or decreased by 1,five numbers namely, 169, 175, 155, 185, and 187 are composite numbers. Thus we have 11 prime numbers between 150 and 200. We know 2,3, and 5 are prime numbers. Similarly 11, 13, 17, 19 are prime numbers

hope it helps you

please mark me as brainlist

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Order the numbers from least to greatest. 9/5, -2.5,-1.1, -4/5, 0.8
prohojiy [21]

Answer:

-4/5, -2.5, -1.1, 0.8, 9/5

Step-by-step explanation:

7 0
2 years ago
There were 58 adults who completed the 16-mile charity bike ride. There were 65 children who completed the 10-mile charity bike
TiliK225 [7]
58*16= 928 (total adult miles)
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Add them together to get the total distance travelled= 928+650= 1578 miles

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3 0
3 years ago
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A chef plans to mix 100% vinegar with Italian dressing, The Italian dressing contains 8% Vinegar,
kolezko [41]

Answer:

  • 15 mL of 100% vinegar
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Step-by-step explanation:

Let v represent the amount of 100% vinegar to be included in the mixture. Then the amount of vinegar in the overall mixture is ...

  1.00v + 0.08(60 -v) = 0.31(60)

  0.92v = 60(0.23) . . . . . . . collect terms, subtract .08(60)

  v = 60(0.23/0.92) = 15 . . . mL of vinegar

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15 mL of vinegar and 45 mL of Italian dressing should be used.

3 0
3 years ago
The graph below shows the hours students spent studying and their language arts test scores.
Alexandra [31]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Chris tried to rewrite the expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}(4
crimeas [40]

We have been given an expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}. We have been given steps how Chris tried to solve the given expression. We are asked to choose the correct option about Chris's work.

Let us simplify our given expression.

Using exponent property, a^m\cdot a^n=a^{m+n}, we cab rewrite our given expression as:

\left( 4^{-2+(-3)} \right)^{3}

\left( 4^{-5} \right)^{3}

Now we will use exponent property (a^m)^n=a^{m\cdot n}to further simplify our expression.

\left( 4^{-5} \right)^{3}= 4^{-5\cdot 3}

\left( 4^{-5} \right)^{3}= 4^{-15}

Therefore, Chris made mistake in step 2.

8 0
3 years ago
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