Have a nice day, be safe and healthy :)
Hope this helped
<u>formula: </u>
(a+b)^2
= a^2+2ab+b^2
Here, we have x^2 (as in a^2)
and -6x (as in 2ab), which, we're missing the b^2
(I'm not really sure how to describe this but bare with me)
-6/2 (-6 is from the -6x) = -3 (the b)
-3^2 = -3*-3 which is equal to 9 (positive 9)
Writing it out -
x^2-6x+9 = -5
- Addition of inequality -
Since we add 9 to the left side, we have to add 9 to the right side; which gives us:
x^2-6x+9=4
Next, lets put the x^2-6x+9 as in (a+b)^2:
(x-3)^2 = 4
<em>Then let's do the square root of equality (square rooting both sides) :</em>
<u>x-3 = 2</u>
<em>Finally lets add 3 to both sides</em>
<u>x = 5</u>
THE ANSWER IS <u><em>x=5</em></u>
<u><em></em></u>
Have a nice day, be safe + healthy - Hope this helped
Answer:
about 17 meters
Step-by-step explanation:
We can use the Pythagorean theorem to put an upper bound on the height of the bump in the rail. This assumes half the expanded rail length (d+e) is the hypotenuse of a right triangle whose legs are the bump height (b) and the 2500 meter distance (d) from the center of the rail to its end.
The Pythagorean theorem relates these distances this way:
b^2 + d^2 = (d+e)^2
Expanding the square on the right, we can simplify the expression to find b.
b^2 = (d^2 +2de +e^2) -d^2
b^2 = e(2d +e)
b = √(e(2d +e))
Using lengths in meters, we can fill this in to calculate b.
b = √(.06(2·2500 +.06)) = √300.0036
b ≈ 17.32 . . . . meters
_____
<em>Comment on this solution</em>
We don't expect rails to tear loose from the rail bed and rise up to a height matching that of a 3-story building. That is why there are typically expansion joints and shorter rail lengths used in the construction of railways.
The height is a little lower if we take physics into account and distribute the stress in the rail along its length. No doubt the final curve is somewhat more complicated than the triangle we have assumed.
If it were an ellipse, the height might only be 9.4 meters, with the steepest rise occurring near the ends of the rail. The math for this model is beyond the scope of this answer.
X = 2y/5 - 9/5
y = 5x/2 + 9/2
(I don't know if this is correct)
Hope this helps!
Answer:
3/4
Step-by-step explanation:
You can do this two different ways. Both include picking two points where the line crosses a corner. I'm using (0,-1) and (4,2). Now here you can either use
Slope=
or 
If you use the first one start at point (0,-1) and go to point (4,2) and count how many it goes up (rise) and then put that over how many it goes to the right (run).
If you use the second one then plug in the numbers.
y2=second y point
y1=first y point
x2=second x point
x1=first x point
Now just solve.
