Answer:
An <u>Orbital </u>is the probability distribution of an electron in an atom or molecule.
Explanation:
As we know atom consists of sub-particles commonly known as protons, neutrons and electrons. The outer space around the nucleus where the probability of finding electrons is maximum is known as orbital. As the electrons are not precisely ordered around the nucleus hence it is not easy to tell the exact position of an electron.
Hence, four quantum numbers are used to locate the position of electrons around the nucleus.
i) Principle Quantum Number:
This number explains the main energy level which tend to increase in energy as the distance of electrons from nucleus are increased. Principle Quantum Numbers are integer number ranging from one to infinity. Hence, increase in this quantum number results in increase of the size of orbital.
ii) Azimuthal Quantum Number:
This Quantum Number explains the direction of particular orbital in 3-dimensional space. Also it is responsible for the shape of an orbital.
iii) Magnetic Quantum Number:
This Quantum Number also tells the direction of orbital in 3D space with respect to x, y and z axis.
iv) Spin Quantum Number:
This Quantum Number tells about the spin direction of an electron about its axis which may be clockwise or anticlockwise.
At an oceanic/oceanic plate boundary 2 oceanic plates will collide against each other. The older oceanic plate will sub-duct under the newer one. It will sub-duct into magma, and will melt into it. The plate and magma will create a reaction, and will build up pressure. With enough pressure, magma will erupt creating a volcano.
The deflection of alpha particles in Rutherford's experiment proved THE ADDITION OF A SMALL, DENSE NUCLEUS TO THE CENTRE OF THE ATOM.
The answer is astronomy. There is no ÓLOGY´ at the end of it.
Answer:
The mass percentage of bromine in the original compound is 81,12%
Explanation:
<u>Step 1: Calculate moles AgBr</u>
moles AgBr = mass AgBr / molar mass AgBr
= 0.8878 g / 187.77 g/mol
= 0.00472812 moles AgBr
⇒
Since 1 mol AgBr contains 1 mol Br-
Then the amount of moles Br- in the original sample must also have been 0.00472812 moles
<u>Step 2:</u> Calculating mass Br-
mass Br- = molar mass Br x moles Br-
= 79.904 g/mol x 0.00472812 mol
= 0.377796 g Br-
⇒
There were 0.377796 g Br- in the original sample
<u>Step 3:</u> Calculating mass percentage Br-
⇒mass percentage = actual mass Br- / total mass x 100%
% mass Br = 0.377796 g / 0.4657 g x 100 %
= 81.12%