Answer:
percentage change in weight ≈ 10%
Step-by-step explanation:
The dog weighed 48 kg after a diet and after an exercise program the dog had a weight of 43 kg. This means the dog loss weight since the dog weight decreased from an initial value of 48 kg to 43 kg. The decrease in weight can be calculate as
decrease in weight = original weight - new weight
original weight = 48 kg
new weight = 43 kg
decrease in weight = 48 - 43 = 5 kg
Since the weight decrease their will be a percentage decrease in weight.
% decrease = decrease in weight/original weight × 100
% decrease = 5/48 × 100
% decrease = 500/48
% decrease = 10. 42666666667
percentage change in weight ≈ 10%
The answer to this is -8/3
Answer:
The test statistics is 
The p-value is 
Step-by-step explanation:
From the question we are told
The West side sample size is 
The number of residents on the West side with income below poverty level is 
The East side sample size 
The number of residents on the East side with income below poverty level is 
The null hypothesis is 
The alternative hypothesis is 
Generally the sample proportion of West side is
=> 
=> 
Generally the sample proportion of West side is
=> 
=> 
Generally the pooled sample proportion is mathematically represented as
=> 
=> 
Generally the test statistics is mathematically represented as
![z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2} ]} }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B%5C%5E%20%7Bp%7D_1%20-%20%5C%5E%7Bp%7D_2%7D%7B%5Csqrt%7Bp%281-%20p%29%20%5B%5Cfrac%7B1%7D%7Bn_1%20%7D%20%2B%20%5Cfrac%7B1%7D%7Bn_2%7D%20%20%5D%7D%20%20%7D)
=> ![z = \frac{ 0.1315 - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688} ]} }](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B%200.1315%20%20-%200.1628%20%7D%7B%5Csqrt%7B0.1485%281-0.1485%29%20%5B%5Cfrac%7B1%7D%7B578%7D%20%2B%20%5Cfrac%7B1%7D%7B688%7D%20%20%5D%7D%20%20%7D)
=>
Generally the p-value is mathematically represented as
From z-table
So
Explanation:
There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.
<u>Statement</u> . . . . <u>Reason</u>
2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle
3. AD ≅ BD
and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle
4. ∠CAE = ∠CAD +∠DAE
and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate
5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality
6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality
7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality
8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate
9. ∠ACD ≅ ∠BCD . . . . CPCTC
10. DC bisects ∠ACB . . . . definition of angle bisector
Closure for addition and multiplication.
Commutative property for addition and multiplication.
Associative property for addition and multiplication.
Distributive property of multiplication over addition.
Identity for addition and multiplication.
Hope this helps; have a great day!
