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3 years ago

Identify the variables that are continuous. Select all that apply.

Mathematics

1 answer:

bonufazy [111]3 years ago

5 0

<h3>3 Answers:</h3>

Choice A
Choice B
Choice F

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Explanation:

Any item in which you can measure (such as length, width, etc) is a continuous variable. These values can take on any positive decimal value. This is why choices A, B and F are continuous.

Choice C on the other hand isn't continuous. It's a discrete value because the number of desks or any item is a positive whole number (1,2,3,...). So having a value like 1.75 desks doesn't make sense. Therefore, we can rule out choice C.

We rule out choices D and E because they aren't quantitative variables. Instead, they are qualitative. They deal with non-numerical aspects of statistics.

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salantis [7]

17) replace the given number for "x" and evaluate

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3² + 2(3) + 1

= 9 + 6 + 1

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(-4)² + 2(-4) + 1

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(-22.872)² + 2(-22.872) + 1

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18) The dependent variable is affected by the other variable and is the "output" The independent variable is the input.

a) y = 3x - 5; "x" is the independent variable

b) the time of day is the independent variable (you would input the time of day to calculate the temperature).

19) Let the x-axis represent the length of the lumber cut off and the y-axis represent the length of the lumber remaining.

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4 years ago

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Step-by-step explanation:

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3 years ago

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73

faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]

Therefore,

CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})$

Thus,

Lower limit of CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}})$

Lower limit of CI = $(98.3 - \frac{2.62\times0.73}{\sqrt{103}})$

Lower limit of CI = 98.11

and,

Upper limit of CI = $(Mean + \frac{t\times\sigma}{\sqrt{n}})$

Upper limit of CI = $(98.3 + \frac{2.62\times0.73}{\sqrt{103}})$

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F

7 0

3 years ago

The sum of a 3 digit number and a 1 digit number is 217. The product of the numbers is 642. If one number is between 200 and 225

algol [13]

Let, the numbers be "x" and "y". Consider "x" as the triple digit number.
Now, according to the question,
x + y = 217..........................equation (1)

x * y = 642............................equation (2)

Now,
Taking equation (2),
x * y = 642
y = 642 / x..................................equation (3)

Now, Taking equation (1),
$x+y=217$

Substituting the value of y from equation (3), we get,

$x+ \frac{642}{x} =217$

$\frac{x *x+642}{x} =217$

$x^{2} +642 =217*x$

$x^{2} +642 =217x$

$x^{2} +642-217x =0$

$x^{2} -217x+642 =0$

$x^{2} -3x-214x+642 =0$

$x(x-3)-214(x-3)=0$

$(x-3)(x-214)=0$

Using zero product property,
EITHER,
x - 3 = 0
x = 3
OR,
x - 214 = 0
x = 214
Since, "x" is the triple digit number, x = 214.
Now,
Taking equation (2),
x * y = 642
Substituting the value of "x" in the equation, we get,
(214) * y = 642
y = 642 / 214
y = 3

So, the numbers are 214 and 3.

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3 years ago

What is the sum of the degrees of the interior angles of a 19-gon?

emmasim [6.3K]

Sum of interior angles formula = (n-2) x 180
where n = number of sides

so,
( 19-2 ) x 180
= 17 x 180
= 3060

ans : A

hope it helps :)

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4 years ago