The given equality hold true when x = 2.
Put x = 2 in inequality.
2(2) + 3 = 4+3 = 7 = R.H.S.
For x = 4 and 6, L.H.S(2x+3) is greater than 7.
Hence for x = 2, 4 and 6, the above inequality holds true.
Hope this helps!
Answer:
skakaaja
Step-by-step explanation:
aamnanananan
If you're completing the square the answer is in the image.
expression
x^2 + 5x - 5=ax^2+bx+c
a=1, b=5, c=-5, and you can solve it that way.
8 is the answer to your question